This is MetaPost, C Version 0.64 (preloaded mem=trap 98.1.28) 28 JAN 1998 11:18 ** &trap trap (trap.mp {if} {known(0)} {not(true)} {false} {known("")} {true} /*\`'@#->begingroup.message(SUFFIX1)&str(SUFFIX0)&jobname&char.ASCII'`&s tr(SUFFIX2)!endgroup (SUFFIX0)<-/*\ (SUFFIX1)<-`' (SUFFIX2)<-pass2 {begingroup} {message} `'->begingroup'`endgroup (SUFFIX0)<- (SUFFIX1)<-`' {begingroup} '`->"\*/" {endgroup} {("\*/")&("/*\")} {jobname} {("\*//*\")&("trap")} '`->"\*/" {ASCII("\*/")} {char(92)} {("\*//*\trap")&("\")} {("\*//*\trap\")&("pass2!")} \*//*\trap\pass2! {endgroup} {nonstopmode} {outer} {let} {delimiters} ! Missing symbolic token inserted. INACCESSIBLE l.22 ...t next=\; delimiters ^~7 ! fi Sorry: You can't redefine a number, string, or expr. I've inserted an inaccessible symbol so that your definition will be completed without mixing me up too badly. ! Extra tokens will be flushed. ! l.22 ... next=\; delimiters ^~7! fi I've just read as much of that statement as I could fathom, so a semicolon should have been next. It's very puzzling... but I'll try to get myself back together, by ignoring everything up to the next `;'. Please insert a semicolon now in front of anything that you don't want me to delete. (See Chapter 27 of The METAFONTbook for an example.) ! Forbidden token found while scanning to the end of the statement. ; \ l.23 next\ ; % the second pass will now compute silently; the ... A previous error seems to have propagated, causing me to read past where you wanted me to stop. I'll try to recover; but if the error is serious, you'd better type `E' or `X' now and fix your file. {\} {batchmode} ! An expression can't begin with `endgroup'. 0 endgroup l.24 batchmode; ^~7,endgroup pausing:=1; exitif p exitif bool... I'm afraid I need some sort of value in order to continue, so I've tentatively inserted `0'. You may want to delete this zero and insert something else; see Chapter 27 of The METAFONTbook for an example. ! Missing ` INACCESSIBLE' has been inserted. endgroup l.24 batchmode; ^~7,endgroup pausing:=1; exitif p exitif bool... I found no right delimiter to match a left one. So I've put one in, behind the scenes; this may fix the problem. ! Extra `endgroup'. endgroup l.24 batchmode; ^~7,endgroup pausing:=1; exitif p exitif bool... I'm not currently working on a `begingroup', so I had better not try to end anything. {pausing:=1} {exitif} {exitif} {pencircle} {endfor} ! Extra `endfor'. l.24 ...ean pen pencircle endfor I'm not currently working on a for loop, so I had better not try to end anything. {scantokens} {begingroup} {message} {char(0)} {("^^@")&("watch this")} ^^@watch this {-(1)} {char(-1)} {("pair p[],';")&("^^ff")} {endgroup} {pen(pen)} {boolean(true)} {true} ! No loop is in progress. pair pair p[],';^^ff path l.26 path p[][]p,w,qw; qw=(1,-2)..(2,-1)..(2.5,0.5)..(1,2)..(... Why say `exitif' when there's nothing to exit from? >> p ! Undefined condition will be treated as `false'. pair pair p[],';^^ff path l.26 path p[][]p,w,qw; qw=(1,-2)..(2,-1)..(2.5,0.5)..(1,2)..(... The expression shown above should have had a definite true-or-false value. I'm changing it to `false'. {false} ! Missing `;' has been inserted. pair pair p[],';^^ff path l.26 path p[][]p,w,qw; qw=(1,-2)..(2,-1)..(2.5,0.5)..(1,2)..(... After `exitif ' I expect to see a semicolon. I shall pretend that one was there. {pair} ! Text line contains an invalid character. pair p[],';^^ff path l.26 path p[][]p,w,qw; qw=(1,-2)..(2,-1)..(2.5,0.5)..(1,2)..(... A funny symbol that I can't read has just been input. Continue, and I'll forget that it ever happened. {path} {-(2)} {-(1)} {turningnumber((xpart ',ypart '))} Path at line 26, before choices: (1,-2){curl 1} ..(2,-1) ..(2.5,0.5) ..(1,2) ..{curl 1}(0,2.5) Path at line 26, after choices: (1,-2)..controls (1.37755,-1.71404) and (1.71404,-1.37755) ..(2,-1)..controls (2.33353,-0.55965) and (2.59729,-0.04124) ..(2.5,0.5)..controls (2.36812,1.23369) and (1.6712,1.65662) ..(1,2)..controls (0.66821,2.16974) and (0.33485,2.33641) ..(0,2.5) {(unknown path qw)=(path)} {numeric} ! Enormous number has been reduced. l.27 ...[$] ]]=10000000000000000 ; "this string constant is in... I can't handle numbers bigger than 32767.99998; so I've changed your constant to that maximum amount. {(p[[ [-1] ]])=(32767.99998)} ## p[[ [-1] ]]=32767.99998 ! Value is too large (32767.99998). l.27 ...$] ]]=10000000000000000; "this string constant is inc... The equation I just processed has given some variable a value of 4096 or more. Continue and I'll try to cope with that big value; but it might be dangerous. (Set warningcheck:=0 to suppress this message.) ! Incomplete string token has been flushed. l.27 ...g constant is incomplete Strings should finish on the same line as they began. I've deleted the partial string; you might want to insert another by typing, e.g., `I"new string"'. {string} ! Declared variable conflicts with previous vardef. , l.28 string foo[]p, p~if true:[]; You can't use, e.g., `numeric foo[]' after `vardef foo'. Proceed, and I'll ignore the illegal redeclaration. {if} {true} {true} {boolean} {fi} {showvariable} boolean.boolean=unknown boolean ! OK. l.29 ...n; showvariable boolean; {inner} {def} {outer} {picture} {pen} ! Illegal suffix of declared variable will be flushed. [ "a" l.31 pen p~[]~,q["a" ,qq; p~1~=q=pencircle scaled mexp(-3016.5... Variables in declarations must consist entirely of names and collective subscripts, e.g., `x[]a'. Are you trying to use a reserved word in a variable name? I'm going to discard the junk I found here, up to the next comma or the end of the declaration. {pencircle} {-(3016.57654)} {mexp(-3016.57654)} {(pen)scaled(0)} {(unknown pen q)=(pen)} {(unknown pen p~1~)=(pen)} {transform} ! Illegal suffix of declared variable will be flushed. 0 l.32 transform p,pp0 ; if p=p:qq=makepen((7,0)..cycle) xscaled... Variables in declarations must consist entirely of names and collective subscripts, e.g., `x[]a'. Explicit subscripts like `x15a' aren't permitted. I'm going to discard the junk I found here, up to the next comma or the end of the declaration. {if} {((xpart p,ypart p,xxpart p,xypart p,yxpart p,yypart p))=((xpart p,ypart p,xxpart p,xypart p,yxpart p,yypart p))} {true} Path at line 32, before choices: (7,0) ..cycle Path at line 32, after choices: (7,0)..controls (7,0) and (7,0) ..cycle {makepen(path)} {hex("1000")} ! Number too large (4096). ; l.32 ...cle) xscaled hex "1000"; show qq;fi I have trouble with numbers greater than 4095; watch out. (Set warningcheck:=0 to suppress this message.) {(pen)xscaled(4096)} {(unknown pen qq)=(pen)} {show} >> Pen at line 32: pencircle transformed (28672,0,0,0,0,0) ! OK. l.32 ...aled hex "1000";show qq; fi {fi} Path at line 33, before choices: (4,1) ..(1,2) ..(5,3) ..(3,2) ..(1,1) ..(0,1) ..(1,0) ..cycle Path at line 33, after choices: (4,1)..controls (3.72015,2.36482) and (1.84834,1.36037) ..(1,2)..controls (-5.16994,6.65202) and (8.52596,9.85889) ..(5,3)..controls (4.6365,2.29291) and (3.69041,2.34465) ..(3,2)..controls (2.30983,1.65547) and (1.78375,0.86862) ..(1,1)..controls (0.63611,1.06099) and (0.23091,1.28844) ..(0,1)..controls (-0.3216,0.5983) and (0.24828,0.12357) ..(1,0)..controls (2.58165,-0.25998) and (4.23677,-0.15471) ..cycle {makepen(path)} {qq:=pen} {show} >> Pen at line 33: (0,1) .. (1,0) .. (4,1) .. (5,3) .. (1,2) .. cycle ! OK. l.33 .....(1,0)..cycle);show qq; {vardef} ! Missing parameter type; `expr' will be assumed. ) l.34 ...ext suffix a,b endtext() )suffix@=show #@; p.a.b() end... You should've had `expr' or `suffix' or `text' here. {expandafter} {\} {let} \\->=show {outer} {((6,12))-((xpart p7,ypart p7))} {((0,1))transformed((xpart p,ypart p,xxpart p,xypart p,yxpart p,yypart p ))} {(x)-(x)} {(2)/(0)} >> 2 ! Division by zero. , l.36 ...)transformed p=(2/(x-x), 3/0)transformed p; You're trying to divide the quantity shown above the error message by zero. I'm going to divide it by one instead. ! Division by zero. l.36 ...ansformed p=(2/(x-x),3/0 )transformed p; I'll pretend that you meant to divide by 1. {((2,3))transformed((xpart p,ypart p,xxpart p,xypart p,yxpart p,yypart p ))} {((linearform,linearform))=((linearform,linearform))} ## yxpart p=-yypart p ## xxpart p=-xypart p {((-xpart p7+6,-ypart p7+12))=((linearform,linearform))} ## ypart p7=-ypart p-yypart p+12 ## xpart p7=-xpart p-xypart p+6 {\} {if} {string(unknown string p~[-1])} {true} {(p0.1 0.2)-(p0.1 0.2)} ! The token `endtext' is no longer a right delimiter. l.37 ...1.2-p.1.199999,1 endtext transformed p; Strange: This token has lost its former meaning! I'll read it as a right delimiter this time; but watch out, I'll probably miss it later. {((0,1))transformed((xpart p,ypart p,-xypart p,xypart p,-yypart p,yypart p))} {((linearform,linearform))=((linearform,linearform))} ## ypart p=-yypart p+6 #### ypart p7=6 ## xpart p=-xypart p+3 #### xpart p7=3 {(unknown path p1 2p)=((3,6))} {showstopping:=0} {showvariable} p=(-xypart p+3,-yypart p+6,-xypart p,xypart p,-yypart p,yypart p) p[]=pair p[][]=numeric p[][]p=unknown path p[][]p~=macro:(SUFFIX2)(SUFFIX3)(EXPR4)->begingroup ETC. p[]~=unknown boolean p~=path p~[]=unknown string p~[]~=unknown pen p~[]~[][]=unknown picture p~[-1]=unknown string p~[-1] p~1~=pen p[[ [] ]]=numeric p[[ [-1] ]]=32767.99998 p0.1 0.2=p0.1 0.2 p1 2p=path p7=(3,6) {((-xypart p+3,-yypart p+6,-xypart p,xypart p,-yypart p,yypart p))=((-xy part p+3,-yypart p+6,-xypart p,xypart p,-yypart p,yypart p))} {let} {let} {xxpart((-xypart p+3,-yypart p+6,-xypart p,xypart p,-yypart p,yypart p)) } {(-xypart p)+(0.002)} {yxpart((-xypart p+3,-yypart p+6,-xypart p,xypart p,-yypart p,yypart p)) } {((xpart p2,ypart p2))-((xpart p1,ypart p1))} {(1)*((linearform,linearform))} {((xpart p1,ypart p1))+((linearform,linearform))} {(y)+(0.00002)} {yypart((-xypart p+3,-yypart p+6,-xypart p,xypart p,-yypart p,yypart p)) } {xypart((-xypart p+3,-yypart p+6,-xypart p,xypart p,-yypart p,yypart p)) } {((5,y))=((yypart p,xypart p))} ## y=xypart p ## yypart p=5 #### ypart p=1 #### yxpart p=-5 {((5,xypart p+0.00002))=((5,xypart p))} {((xpart p2,ypart p2))=((5,xypart p))} ## ypart p2=xypart p ## xpart p2=5 {((-xypart p+0.002,-5))=((5,xypart p))} ## xypart p=-5 #### ypart p2=-5 #### y=-5 #### xpart p=8 #### xxpart p=5 ! Inconsistent equation (off by -0.002). ; l.39 ...,y)=(yypart p,xypart p); The equation I just read contradicts what was said before. But don't worry; continue and I'll just ignore it. Path at line 40, before choices: (0,0)..controls (15,4) and (-15,-12) ..(4,0) ..cycle Path at line 40, after choices: (0,0)..controls (15,4) and (-15,-12) ..(4,0)..controls (17.52783,8.54388) and (-15.45978,-4.12262) ..cycle {reverse(path)} {(path)transformed((8,1,5,-5,-5,5))} {(path)=(unknown path p2 3p)} p1 2p~(SUFFIX2)(SUFFIX3)(EXPR4)->begingroup.show(SUFFIX0);p(SUFF IX2)(SUFFIX3)((EXPR4)endgroup (SUFFIX0)<-p1 2p (SUFFIX1)<-~ (SUFFIX2)<- (SUFFIX3)<-2 3p~ ! A primary expression can't begin with `right delimiter that matches (' . 0 ) l.41 ...000000001]2p~(,[2]3p~,-) =p~1~2[pausing]; I'm afraid I need some sort of value in order to continue, so I've tentatively inserted `0'. You may want to delete this zero and insert something else; see Chapter 27 of The METAFONTbook for an example. {-(0)} (EXPR4)<-0 (SUFFIX5)<- {begingroup} {show} >> Path at line 41: (3,6) p2 3p~(SUFFIX2)(SUFFIX3)(EXPR4)->begingroup.show(SUFFIX0);p(SUFF IX2)(SUFFIX3)((EXPR4)endgroup (SUFFIX0)<-p2 3p (SUFFIX1)<-~ ! Missing `,' has been inserted. (0) p1 2p~->...IX2)(SUFFIX3)((EXPR4) endgroup = l.41 ...00000001]2p~(,[2]3p~,-)= p~1~2[pausing]; I've finished reading a macro argument and am about to read another; the arguments weren't delimited correctly. You might want to delete some tokens before continuing. (SUFFIX2)<- ! Missing `,' has been inserted. (0) p1 2p~->...IX2)(SUFFIX3)((EXPR4) endgroup = l.41 ...00000001]2p~(,[2]3p~,-)= p~1~2[pausing]; I've finished reading a macro argument and am about to read another; the arguments weren't delimited correctly. You might want to delete some tokens before continuing. (SUFFIX3)<- ! Missing `)' has been inserted. endgroup = l.41 ...00000001]2p~(,[2]3p~,-)= p~1~2[pausing]; I've gotten to the end of the macro parameter list. You might want to delete some tokens before continuing. (EXPR4)<-0 (SUFFIX5)<- {begingroup} {show} >> Path at line 41: (8,1)..controls (-48.68579,57.68579) and (52.91974,-43.91974) ..(28,-19)..controls (-7,16) and (63,-54) ..cycle >> (8,1,5,-5,-5,5) ! Isolated expression. ( p2 3p~->...;p(SUFFIX2)(SUFFIX3)( (EXPR4)endgroup endgroup = l.41 ...00000001]2p~(,[2]3p~,-)= p~1~2[pausing]; I couldn't find an `=' or `:=' after the expression that is shown above this error message, so I guess I'll just ignore it and carry on. ! Extra tokens will be flushed. ( p2 3p~->...;p(SUFFIX2)(SUFFIX3)( (EXPR4)endgroup endgroup = l.41 ...00000001]2p~(,[2]3p~,-)= p~1~2[pausing]; I've just read as much of that statement as I could fathom, so a semicolon should have been next. It's very puzzling... but I'll try to get myself back together, by ignoring everything up to the next `;'. Please insert a semicolon now in front of anything that you don't want me to delete. (See Chapter 27 of The METAFONTbook for an example.) {endgroup} {endgroup} {(vacuous)=(unknown picture p~1~2 1)} >> vacuous >> unknown picture p~1~2 1 ! Equation cannot be performed (vacuous=unknown picture). ; l.41 ...2]3p~,-)=p~1~2[pausing]; I'm sorry, but I don't know how to make such things equal. (See the two expressions just above the error message.) {vardef} Runaway definition? if.p(SUFFIX1)(SUFFIX1)=(SUFFIX1)(SUFFIX1)p.fi ! Forbidden token found while scanning the definition of p~[]. enddef ; l.42 ...iary t:=if p@ @=@ @p fi; vardef p[][]p~[]=BAD; inner ;; I suspect you have forgotten an `enddef', causing me to read past where you wanted me to stop. I'll try to recover; but if the error is serious, you'd better type `E' or `X' now and fix your file. {vardef} ! This variable already starts with a macro. l.42 ...@p fi; vardef p[][]p~[]= BAD; inner ;; After `vardef a' you can't say `vardef a.b'. So I'll have to discard this definition. Runaway definition? BAD ! Forbidden token found while scanning the definition of a bad variable. enddef ; l.42 ...i; vardef p[][]p~[]=BAD; inner ;; I suspect you have forgotten an `enddef', causing me to read past where you wanted me to stop. I'll try to recover; but if the error is serious, you'd better type `E' or `X' now and fix your file. {inner} {show} {-(2)} p~[-2]@#->begingroup.if.p(SUFFIX1)(SUFFIX1)=(SUFFIX1)(SUFFIX1) p.fi.endgroup (SUFFIX0)<-p~ (SUFFIX1)<-[-2] (SUFFIX2)<-~ ! A tertiary expression can't begin with `['. 0 [ (3000) , l.43 show p~[-2]~[3000, x]++4000>path p3; showvariable p,P; I'm afraid I need some sort of value in order to continue, so I've tentatively inserted `0'. You may want to delete this zero and insert something else; see Chapter 27 of The METAFONTbook for an example. {(x)-(3000)} {(0)*(x-3000)} {(3000)+(0)} {(3000)++(4000)} (EXPR3)<-4999.99998 {begingroup} {if} {(p[-2][-2])=(-2)} >> p[-2][-2]+2 ! Unknown relation will be considered false. [-2] p~[-2]->...1)=(SUFFIX1)(SUFFIX1) p.fi.endgroup > l.43 show p~[-2]~[3000,x]++4000> path p3; showvariable p,P; Oh dear. I can't decide if the expression above is positive, negative, or zero. So this comparison test won't be `true'. {false} ! Missing `:' has been inserted. [-2] p~[-2]->...1)=(SUFFIX1)(SUFFIX1) p.fi.endgroup > l.43 show p~[-2]~[3000,x]++4000> path p3; showvariable p,P; There should've been a colon after the condition. I shall pretend that one was there. {endgroup} {path((xpart p3,ypart p3))} {(vacuous)>(false)} >> vacuous >> false ! Not implemented: (vacuous)>(boolean). ; l.43 ...~[3000,x]++4000>path p3; showvariable p,P; I'm afraid I don't know how to apply that operation to that combination of types. Continue, and I'll return the second argument (see above) as the result of the operation. >> false {showvariable} p=(8,1,5,-5,-5,5) p[]=pair p[][]=numeric p[][]p=unknown path p[][]p~=macro:(SUFFIX2)(SUFFIX3)(EXPR4)->begingroup ETC. p[]~=unknown boolean p~=path p~[]@#=macro:->begingroup.if.p(SUFFIX1)(SUFFIX1) ETC. p[[ [] ]]=numeric p[[ [-1] ]]=32767.99998 p[-2][-2]=p[-2][-2] p0.1 0.2=p0.1 0.2 p1=(xpart p1,ypart p1) p1 2p=path p2=(5,-5) p2 3p=path p3=(xpart p3,ypart p3) p7=(3,6) > P=tag {numeric} {(2)*(alpha)} {(p3~)=(2alpha)} ## alpha=0.5p3~ {(1)/(-1)} {(3)*(beta)} {(p[-1]~)=(3beta)} ## beta=0.33333p[-1]~ {begingroup} {save} {showvariable} > p=tag {(3)*(0.33333(SAVED)p[-1]~)} {((SAVED)p[-1]~)=(1)} ## (SAVED)p[-1]~=1 #### beta=0.33333 {restoring p} {endgroup} {showvariable} p=(8,1,5,-5,-5,5) p[]=pair p[][]=numeric p[][]p=unknown path p[][]p~=macro:(SUFFIX2)(SUFFIX3)(EXPR4)->begingroup ETC. p[]~=numeric p~=path p~[]@#=macro:->begingroup.if.p(SUFFIX1)(SUFFIX1) ETC. p[[ [] ]]=numeric p[[ [-1] ]]=32767.99998 p[-2][-2]=p[-2][-2] p[-1]~=1 p0.1 0.2=p0.1 0.2 p1=(xpart p1,ypart p1) p1 2p=path p2=(5,-5) p2 3p=path p3=(xpart p3,ypart p3) p3~=p3~ p7=(3,6) {def} {def} ! Missing `=' has been inserted. false l.46 ...enddef;def!primary!false ):!fi enddef; The next thing in this `def' should have been `=', because I've already looked at the definition heading. But don't worry; I'll pretend that an equals sign was present. Everything from here to `enddef' will be the replacement text of this macro. {def} {(path)scaled(-1)} Path at line 47, before choices: (1,-2)..controls (1.37755,-1.71404) and (1.71404,-1.37755) ..(2,-1)..controls (2.33353,-0.55965) and (2.59729,-0.04124) ..(2.5,0.5)..controls (2.36812,1.23369) and (1.6712,1.65662) ..(1,2)..controls (0.66821,2.16974) and (0.33485,2.33641) ..(0,2.5) ..(-1,2)..controls (-1.37755,1.71404) and (-1.71404,1.37755) ..(-2,1)..controls (-2.33353,0.55965) and (-2.59729,0.04124) ..(-2.5,-0.5)..controls (-2.36812,-1.23369) and (-1.6712,-1.65662) ..(-1,-2)..controls (-0.66821,-2.16974) and (-0.33485,-2.33641) ..(0,-2.5) ..cycle Path at line 47, after choices: (1,-2)..controls (1.37755,-1.71404) and (1.71404,-1.37755) ..(2,-1)..controls (2.33353,-0.55965) and (2.59729,-0.04124) ..(2.5,0.5)..controls (2.36812,1.23369) and (1.6712,1.65662) ..(1,2)..controls (0.66821,2.16974) and (0.33485,2.33641) ..(0,2.5)..controls (-0.37186,2.68167) and (-0.668,2.25146) ..(-1,2)..controls (-1.37755,1.71404) and (-1.71404,1.37755) ..(-2,1)..controls (-2.33353,0.55965) and (-2.59729,0.04124) ..(-2.5,-0.5)..controls (-2.36812,-1.23369) and (-1.6712,-1.65662) ..(-1,-2)..controls (-0.66821,-2.16974) and (-0.33485,-2.33641) ..(0,-2.5)..controls (0.37186,-2.68167) and (0.668,-2.25146) ..cycle {makepen(path)} {qq:=pen} {show} >> Pen at line 48: (-2.5,-0.5) .. (-1,-2) .. (0,-2.5) .. (1,-2) .. (2,-1) .. (2.5,0.5) .. (1,2) .. (0,2.5) .. (-1,2) .. (-2,1) .. cycle {primarydef} {secondarydef} //-> //-> {pencircle} {length(path)} {(pen)slanted(1)} {((3,6))-((5,-5))} _aa__->if(true {(0.1)*(15)} {odd(1.50009)} {not(false)} {known((8,1,5,-5,-5,5))} {(true)and(true)} (EXPR0)<-true {if} {true} !->false):(EXPR0)fi (EXPR0)<-(5,-5) {false} {(true)or(false)} {true} {fi} {-((5,-5))} {-((5,-5))} {+(1)} {-(1)} >> -1 ! Improper curl has been replaced by 1. ) l.52 {curl- +1) ..tension atleast1..cycle sqrt2++sqrt2***[[]]; A curl must be a known, nonnegative number. ! Missing `}' has been inserted. ) l.52 {curl- +1) ..tension atleast1..cycle sqrt2++sqrt2***[[]]; I've scanned a direction spec for part of a path, so a right brace should have come next. I shall pretend that one was there. Path at line 52, before choices: (-5,5) Path at line 52, after choices: (-5,5) Path at line 52, before choices: (3,6)..controls (5,-5) and (-5,5) ..(-5,5)..tension atleast1 ..{2896.30943,-2896.30934}cycle Path at line 52, after choices: (3,6)..controls (5,-5) and (-5,5) ..(-5,5)..controls (-3.29726,7.86205) and (0.64516,8.35484) ..cycle ! Missing `)' has been inserted. sqrt l.52 ...ion atleast1..cycle sqrt 2++sqrt2***[[]]; I found no right delimiter to match a left one. So I've put one in, behind the scenes; this may fix the problem. {((-2,11))subpath(path)} {reverse(path)} {makepen(path)} **->[[show(EXPR0)*(EXPR1)]] (EXPR0)<-pen (EXPR1)<-pen {begingroup} {show} {(pen)*(pen)} >> pen >> pen ! Not implemented: (pen)*(pen). ]] sqrt l.52 ...ion atleast1..cycle sqrt 2++sqrt2***[[]]; I'm afraid I don't know how to apply that operation to that combination of types. Continue, and I'll return the second argument (see above) as the result of the operation. >> Pen at line 52: (-5,5) .. (3,6) .. cycle {endgroup} (EXPR0)<-vacuous {sqrt(2)} {sqrt(2)} {(1.41422)++(1.41422)} {begingroup} {endgroup} ***->expandafter(EXPR1)scantokens"**oct"(EXPR0) (EXPR0)<-2 (EXPR1)<-vacuous {expandafter} {scantokens} {oct(2)} >> 2 ! Not implemented: oct(known numeric). ; l.52 ...cle sqrt2++sqrt2***[[]]; I'm afraid I don't know how to apply that operation to that particular type. Continue, and I'll simply return the argument (shown above) as the result of the operation. **->[[show(EXPR0)*(EXPR1)]] (EXPR0)<-vacuous (EXPR1)<-2 {begingroup} {show} {(vacuous)*(2)} >> vacuous >> 2 ! Not implemented: (vacuous)*(known numeric). ]] ; l.52 ...cle sqrt2++sqrt2***[[]]; I'm afraid I don't know how to apply that operation to that combination of types. Continue, and I'll return the second argument (see above) as the result of the operation. >> 2 {endgroup} (EXPR0)<-vacuous {-(20.5)} {charcode:=-20.5} {-(2048)} {chardp:=-2048} {shipout} {nullpicture} ! Enormous chardp has been reduced. ; l.53 ...048;shipout nullpicture; Font metric dimensions must be less than 2048pt. [] Edge structure at line 53 (just shipped out): End edges {if} {-(275.50002)} {charexists(-275.50002)} {known(unknown path p0 0p)} {(true)>(false)} {known(path)} {(true)=(true)} {true} {randomseed} ! Missing `:=' has been inserted. charcode l.54 ... p~: randomseed charcode ; fi Always say `randomseed:='. {randomseed:=-20.5} {fi} {randomseed} >> "goof" ! Unknown value will be ignored. ; l.55 randomseed:="goof"; a[($,18++1+-+18),(2,3)]=b[(3,2),(1,$); Your expression was too random for me to handle, so I won't change the random seed just now. {(18)++(1)} {(18.02776)+-+(18)} {((2,3))-((-1,1))} {(a)*((3,2))} {((-1,1))+((3a,2a))} ! Missing `]' has been inserted. ; l.55 ...8),(2,3)]=b[(3,2),(1,$); I've scanned an expression of the form `a[b,c', so a right bracket should have come next. I shall pretend that one was there. {((1,-1))-((3,2))} {(b)*((-2,-3))} {((3,2))+((-2b,-3b))} {((3a-1,2a+1))=((-2b+3,-3b+2))} ## b=-0.66667a+0.33333 ## a=2 #### b=-1 {show} {(^)+(1)} {(~)+(2)} {-(1)} {((^+1,~+2))slanted(-1)} {-(2)} {((linearform,~+2))yscaled(-2)} {-((3,4))} {((linearform,-2~-4))zscaled((-3,-4))} >> (-5~-3^-13,10~-4^+16) {((xpart pp,ypart pp,xxpart pp,xypart pp,yxpart pp,yypart pp))xscaled(9) } {((8,1,5,-5,-5,5))transformed((9xpart pp,ypart pp,9xxpart pp,9xypart pp, yxpart pp,yypart pp))} >> (9xpart pp+72xxpart pp+9xypart pp,ypart pp+8yxpart pp+yypart pp,45xxp art pp-45xypart pp,-45xxpart pp+45xypart pp,5yxpart pp-5yypart pp,-5yxpa rt pp+5yypart pp) {((xpart pp,ypart pp,xxpart pp,xypart pp,yxpart pp,yypart pp))shifted((1 ,2))} {((8,1,5,-5,-5,5))transformed((8,1,5,-5,-5,5))} {((xpart pp+1,ypart pp+2,xxpart pp,xypart pp,yxpart pp,yypart pp))transf ormed((43,-34,50,-50,-50,50))} >> (50xpart pp-50ypart pp-7,-50xpart pp+50ypart pp+16,50xxpart pp-50yxpa rt pp,50xypart pp-50yypart pp,-50xxpart pp+50yxpart pp,-50xypart pp+50yy part pp) {(2)-(1)} {(_0)*(1)} {(1)+(_0)} {-(_0+1)} >> -_0-1 {show} {normaldeviate} {-(-2048)} {uniformdeviate(2048)} {angle((-0.41438,761.67789))} {cosd(90.03117)} {(200)*(-0.00055)} {mexp(-0.10986)} {sqrt(0.99957)} {mlog(0.99979)} {sind(-0.05469)} {floor(-0.00096)} >> -1 {string} {(unknown string s2)=(unknown string s4)} {(unknown string s1)=(unknown string s2)} {(unknown string s3)=(unknown string s5)} {(unknown string s2)=(unknown string s4)} ! Redundant equation. ; l.59 ... s1=s2=s4; s3=s5; s1=s2; if s1<=s4<>(s1<>s3):show[[ch... I already knew that this equation was true. But perhaps no harm has been done; let's continue. {if} {(unknown string s2)<=(unknown string s1)} {(unknown string s2)<>(unknown string s5)} >> unknown string s2 >> unknown string s5 ! Unknown relation will be considered false. ) l.59 ...=s2; if s1<=s4<>(s1<>s3) :show[[char34=s2:=s3]]fi; The quantities shown above have not been equated. {(true)<>(false)} {true} {show} {begingroup} {char(34)} {s2:=unknown string s5} {(""")=(unknown string s2)} {endgroup} {fi} >> vacuous {(0.1)point(path)} {begingroup} {pencircle} {endgroup} {((3.24413,0.64801))penoffset(pen)} {((0.09795,-0.49031))rotated(540)} {((-0.09795,0.49031))/(0.33333)} {-(1.5)} ! Paths don't touch; `&' will be changed to `..'. ) l.61 ...tcontrol-1.5of(p~&cycle) -precontrol1/2of p~(p~)=s1:=s... When you join paths `p&q', the ending point of p must be exactly equal to the starting point of q. So I'm going to pretend that you said `p..q' instead. Path at line 61, before choices: (0,0)..controls (15,4) and (-15,-12) ..(4,0) ..cycle Path at line 61, after choices: (0,0)..controls (15,4) and (-15,-12) ..(4,0)..controls (17.52783,8.54388) and (-15.45978,-4.12262) ..cycle {(-1.5)postcontrol(path)} {(0.5)precontrol(path)} {((-2.75,-5))-((3.75,-1))} ! Missing `of' has been inserted for directiontime. ( l.61 ...cle)-precontrol1/2of p~( p~)=s1:=s4:=s4; I've got the first argument; will look now for the other. {((-6.5,-4))directiontime(path)} {decimal(0.5)} {((-0.29384,1.47095))substring("0.5")} {s4:=unknown string s1} {s1:=unknown string s4} {("0")=(unknown string s1)} {path} {length(" ")} ! Missing `,' has been inserted. } l.62 ...p~[]; p~1=p2{length" "} &cycle; p~1=p2=p~0; p2..contr... I've got the x coordinate of a path direction; will look for the y coordinate next. ! An expression can't begin with `}'. 0 } l.62 ...p~[]; p~1=p2{length" "} &cycle; p~1=p2=p~0; p2..contr... I'm afraid I need some sort of value in order to continue, so I've tentatively inserted `0'. You may want to delete this zero and insert something else; see Chapter 27 of The METAFONTbook for an example. Path at line 62, before choices: (5,-5){4096,0} ..{4096,0}cycle Path at line 62, after choices: (5,-5)..controls (5,-5) and (5,-5) ..cycle {(unknown path p~1)=(path)} {((5,-5))=(unknown path p~0)} {(path)=(path)} ! Redundant or inconsistent equation. ; l.62 ..." "}&cycle; p~1=p2=p~0; p2..controls-p2..cycle=p~2;(p7 An equation between already-known quantities can't help. But don't worry; continue and I'll just ignore it. {-((5,-5))} Path at line 62, before choices: (5,-5)..controls (-5,5) and (-5,5) ..cycle Path at line 62, after choices: (5,-5)..controls (-5,5) and (-5,5) ..cycle {(path)=(unknown path p~2)} {length(path)} Path at line 63, before choices: (3,6)..tension 1.2 ..(5,-5)..controls (5,-5) and (5,-5) ..(5,-5) ..(5,-5)..controls (-5,5) and (-5,5) ..(5,-5){0,4096}..tension 1 and atleast1 ..cycle Path at line 63, after choices: (3,6)..controls (-3.01212,4.82085) and (-1.0424,-6.01257) ..(5,-5)..controls (5,-5) and (5,-5) ..(5,-5)..controls (5,-5) and (5,-5) ..(5,-5)..controls (-5,5) and (-5,5) ..(5,-5)..controls (5,0.02791) and (4.99951,6.39217) ..cycle >> x ! Improper tension has been set to 1. .. l.64 x.. {curl1}-p7{curl hex "IsBad"}..tension.75and.74999..p... The expression above should have been a number >=3/4. {-((3,6))} {hex("IsBad")} >> "IsBad" ! String contains illegal digits. } l.64 ...l1}-p7{curl hex "IsBad"} ..tension.75and.74999..p2{0,1... I zeroed out characters that weren't hex digits. >> 0.74998 ! Improper tension has been set to 1. .. l.64 ...}..tension.75and.74999.. p2{0,1}&p2{_,'}..cycle:=p The expression above should have been a number >=3/4. >> _ ! Undefined x coordinate has been replaced by 0. , l.64 ...and.74999..p2{0,1}&p2{_, '}..cycle:=p I need a `known' x value for this part of the path. The value I found (see above) was no good; so I'll try to keep going by using zero instead. (Chapter 27 of The METAFONTbook explains that you might want to type `I ???' now.) >> (xpart ',ypart ') ! Undefined y coordinate has been replaced by 0. } l.64 ...d.74999..p2{0,1}&p2{_,'} ..cycle:=p I need a `known' y value for this part of the path. The value I found (see above) was no good; so I'll try to keep going by using zero instead. (Chapter 27 of The METAFONTbook explains that you might want to type `I ???' now.) Path at line 64, before choices: (3,6)..controls (-3.01212,4.82085) and (-1.0424,-6.01257) ..(5,-5)..controls (5,-5) and (5,-5) ..(5,-5)..controls (5,-5) and (5,-5) ..(5,-5)..controls (-5,5) and (-5,5) ..(5,-5)..controls (5,0.02791) and (4.99951,6.39217) ..(3,6) ..{curl 1}(-3,-6){curl 2989}..tension 0.75 and 1 ..{0,4096}(5,-5){curl 1} ..cycle Path at line 64, after choices: (3,6)..controls (-3.01212,4.82085) and (-1.0424,-6.01257) ..(5,-5)..controls (5,-5) and (5,-5) ..(5,-5)..controls (5,-5) and (5,-5) ..(5,-5)..controls (-5,5) and (-5,5) ..(5,-5)..controls (5,0.02791) and (4.99951,6.39217) ..(3,6)..controls (-2.44821,4.93144) and (-5.41408,-1.00029) ..(-3,-6)..controls (-3.70045,-12.19485) and (5,-11.61679) ..(5,-5)..controls (12.45406,-3.75087) and (10.41669,7.45464) ..cycle >> path ! Improper `:=' will be changed to `='. l.64 ...p2{0,1}&p2{_,'}..cycle:= p I didn't find a variable name at the left of the `:=', so I'm going to pretend that you said `=' instead. {(path)=(unknown path p~4)} {-(9)} {((3.5001,7.00002))subpath(path)} {((-9,9))subpath(path)} {(path)=(unknown path p~6)} {show} >> Path at line 66: (-2.5,2.5)..controls (-2.49893,2.49893) and (0.00107,-0.00107) ..(5,-5)..controls (5,0.02791) and (4.99951,6.39217) ..(3,6)..controls (-2.44821,4.93144) and (-5.41408,-1.00029) ..(-3,-6)..controls (-3.70045,-12.19485) and (5,-11.61679) ..(5,-5)..controls (5.0001,-4.99998) and (5.00021,-4.99997) ..(5.00032,-4.99995) {((1,2))directiontime(path)} >> 1 {-(1.00002)} {((1,-1.00002))directiontime(path)} >> 3.24937 Path at line 67, before choices: (0,0)..controls (1,1) and (0,1) ..(1,0) Path at line 67, after choices: (0,0)..controls (1,1) and (0,1) ..(1,0) {(unknown path p~3)=(path)} {show} Path at line 67, before choices: (5,-5){-2896.30943,-2896.30934} ..{1831.78674,3663.57385}cycle Path at line 67, after choices: (5,-5)..controls (5,-5) and (5,-5) ..cycle >> Path at line 67: (5,-5)..controls (5,-5) and (5,-5) ..cycle {((0.31416,1))subpath(path)} {((1,1))directiontime(path)} {(1)-(0.31416)} {(0.27097)*(0.68584)} {(0.31416)+(0.18584)} >> 0.5 {((0,0.25))subpath(path)} {((0.25,1))subpath(path)} Path at line 69, before choices: (0,0)..controls (0.25,0.25) and (0.375,0.4375) ..(0.4375,0.5625)..controls (0.625,0.9375) and (0.25,0.75) ..(1,0) Path at line 69, after choices: (0,0)..controls (0.25,0.25) and (0.375,0.4375) ..(0.4375,0.5625)..controls (0.625,0.9375) and (0.25,0.75) ..(1,0) ! Missing `endtext' has been inserted. ; l.69 ...~3)shifted begintext1,0; I found no right delimiter to match a left one. So I've put one in, behind the scenes; this may fix the problem. {(path)shifted((1,0))} {(unknown path p~5)=(path)} {(2/3)*((xpart ',ypart '))} {((0.66667xpart ',0.66667ypart '))zscaled((xpart ',ypart '))} >> (0,0,xpart ',-ypart ',ypart ',xpart ') ! Transform components aren't all known. { l.70 p~3:=2/3'zscaled'{ p~3}..controls(2,2/3(3))and penoffset(... I'm unable to apply a partially specified transformation except to a fully known pair or transform. Proceed, and I'll omit the transformation. >> 0.66667xpart ' ! Undefined x coordinate has been replaced by 0. { l.70 p~3:=2/3'zscaled'{ p~3}..controls(2,2/3(3))and penoffset(... I need a `known' x value for this part of the path. The value I found (see above) was no good; so I'll try to keep going by using zero instead. (Chapter 27 of The METAFONTbook explains that you might want to type `I ???' now.) >> 0.66667ypart ' ! Undefined y coordinate has been replaced by 0. { l.70 p~3:=2/3'zscaled'{ p~3}..controls(2,2/3(3))and penoffset(... I need a `known' y value for this part of the path. The value I found (see above) was no good; so I'll try to keep going by using zero instead. (Chapter 27 of The METAFONTbook explains that you might want to type `I ???' now.) >> path ! Undefined coordinates have been replaced by (0,0). } l.70 p~3:=2/3'zscaled'{p~3} ..controls(2,2/3(3))and penoffset(... I need x and y numbers for this part of the path. The value I found (see above) was no good; so I'll try to keep going by using zero instead. (Chapter 27 of The METAFONTbook explains that you might want to type `I ???' now.) {(2/3)*(3)} {(1/2)*(x)} {((0.5x,-5))penoffset((0,1))} >> (0.5x,-5) >> (0,1) ! Not implemented: penoffset(unknown pair)of(pair). ( l.70 ...enoffset(1/2x,y)of(0,1)( 1,0); I'm afraid I don't know how to apply that operation to that combination of types. Continue, and I'll return the second argument (see above) as the result of the operation. ! Missing `..' has been inserted. ( l.70 ...enoffset(1/2x,y)of(0,1)( 1,0); A path join command should end with two dots. Path at line 70, before choices: (0,0)..controls (2,2) and (0,1) ..(1,0) Path at line 70, after choices: (0,0)..controls (2,2) and (0,1) ..(1,0) {p~3:=path} {show} {reverse(path)} {(path)intersectiontimes(path)} >> (0.17227,0.28339) {(0.17227)point(path)} >> (0.71329,0.78188) {(1)-(0.28339)} {(0.71661)point(path)} >> (0.7133,0.78189) {show} {(path)shifted((0.01,0))} {(path)intersectiontimes(path)} {xpart((1.47693,1.18973))} {(1.47693)point(path)} {(path)shifted((0.01,0))} {(path)intersectiontimes(path)} {ypart((1.47693,1.18973))} {(1.18973)point(path)} {((1.50499,0.71521))-((1.495,0.71521))} >> (0.01,0) {begingroup} {-(1)} {-(1.00002)} {(-1)+-+(-1.00002)} ! Pythagorean subtraction 1+-+1.00002 has been replaced by 0. l.74 [[ e[-1+-+ -1.00001] =nullpicture; addto e1 also[[ Since I don't take square roots of negative numbers, I'm zeroing this one. Proceed, with fingers crossed. {nullpicture} {(unknown picture e0)=(picture)} {addto} {begingroup} {addto} {(path)scaled(3)} {(unknown picture e1)=(unknown picture e2)} {(picture)=(unknown picture e1)} {nullpicture} {endgroup} {show} >> Edge structure at line 76: Filled pen stroke : (3,0)..controls (3.75,0.75) and (4.125,1.3125) ..(4.3125,1.6875)..controls (4.875,2.8125) and (3.75,2.25) ..(6,0) butt ends, mitered joins limited 1 with pen pencircle transformed (0,0,0,0,0,0) End edges {-(3)} {(picture)shifted((-3,0))} >> Edge structure at line 76: Filled pen stroke : (0,0)..controls (0.75,0.75) and (1.125,1.3125) ..(1.3125,1.6875)..controls (1.875,2.8125) and (0.75,2.25) ..(3,0) butt ends, mitered joins limited 1 with pen pencircle transformed (0,0,0,0,0,0) End edges {endgroup} {addto} {-(2)} {(picture)shifted((-2,-1))} {-(4)} {(picture)shifted((-4,-1))} {e1:=picture} {addto} {turningnumber(path)} {oct("180")} >> "180" ! String contains illegal digits. ++ l.79 ...en qq xscaled(oct"180"++ 1) rotated-angle(64,$) shifte... I zeroed out characters that weren't in the range 0..7. {(64)++(1)} {(pen)xscaled(64.00781)} {angle((64,-1))} {-(-0.89517)} {(pen)rotated(0.89517)} {(pen)shifted((9,8))} {show} >> Edge structure at line 80: Filled pen stroke : (-1,-1)..controls (-0.25,-0.25) and (0.125,0.3125) ..(0.3125,0.6875)..controls (0.875,1.8125) and (-0.25,1.25) ..(2,-1) butt ends, mitered joins limited 1 with pen pencircle transformed (0,0,0,0,0,0) Filled pen stroke : (-3,-2)..controls (-2.25,-1.25) and (-1.875,-0.6875) ..(-1.6875,-0.3125)..controls (-1.125,0.8125) and (-2.25,0.25) ..(0,-2) butt ends, mitered joins limited 1 with pen pencircle transformed (0,0,0,0,0,0) Filled pen stroke colored (0.4,1,0): (0,9) butt ends, mitered joins limited 1 with pen (-150.99219,4.99976) .. (-54.96875,5.00012) .. (9.03906,5.5003) .. (73.03125,7.00037) .. (137.01563,9.00037) .. (168.99219,11.00024) .. (72.96875,10.99988) .. (8.96094,10.4997) .. (-55.03125,8.99963) .. (-119.01563,6.99963) .. cycle End edges {charcode:=5} {chardp:=5} {-(1.5)} {xoffset:=-1.5} ## xoffset=-1.5 {shipout} [5 Envelope spec at line 80: (0,9) % beginning with offset (-150.99219,4.99976) ..controls (0,9) and (0,9) ..(0,9) % counterclockwise to offset (-150.99219,4.99976) & cycle ] Edge structure at line 80 (just shipped out): Filled pen stroke : (-1,-1)..controls (-0.25,-0.25) and (0.125,0.3125) ..(0.3125,0.6875)..controls (0.875,1.8125) and (-0.25,1.25) ..(2,-1) butt ends, mitered joins limited 1 with pen pencircle transformed (0,0,0,0,0,0) Filled pen stroke : (-3,-2)..controls (-2.25,-1.25) and (-1.875,-0.6875) ..(-1.6875,-0.3125)..controls (-1.125,0.8125) and (-2.25,0.25) ..(0,-2) butt ends, mitered joins limited 1 with pen pencircle transformed (0,0,0,0,0,0) Filled pen stroke colored (0.4,1,0): (0,9) butt ends, mitered joins limited 1 with pen (-150.99219,4.99976) .. (-54.96875,5.00012) .. (9.03906,5.5003) .. (73.03125,7.00037) .. (137.01563,9.00037) .. (168.99219,11.00024) .. (72.96875,10.99988) .. (8.96094,10.4997) .. (-55.03125,8.99963) .. (-119.01563,6.99963) .. cycle End edges {nullpicture} {(unknown picture e3)=(picture)} {showstats} Memory usage 1178&115 (2344 still untouched) String usage 22&84 (1245&9620 now untouched) {addto} Path at line 81, before choices: (0.5,0){curl 1} ..{curl 1}(3.5,1.5) Path at line 81, after choices: (0.5,0)..controls (1.5,0.5) and (2.5,1) ..(3.5,1.5) Path at line 82, before choices: (1,1) ..cycle Path at line 82, after choices: (1,1)..controls (1,1) and (1,1) ..cycle {makepen(path)} {(pen)yscaled(1.5)} {q:=pen} {-(14.5)} {charext:=-14.5} {chardp:=-14.5} {chardx:=-14.5} ## chardx=-14.5 {charcode:=6} {shipout} [6] Edge structure at line 83 (just shipped out): Filled pen stroke : (3,0)..controls (3.75,0.75) and (4.125,1.3125) ..(4.3125,1.6875)..controls (4.875,2.8125) and (3.75,2.25) ..(6,0) butt ends, mitered joins limited 1 with pen pencircle transformed (0,0,0,0,0,0) End edges Path at line 84, before choices: (0,0){curl 1} ..(1,0.5) ..(5,1.5) ..(7,2.5) ..(12,3.5) ..{curl 1}(13,4) Path at line 84, after choices: (0,0)..controls (0.3153,0.20053) and (0.6504,0.36807) ..(1,0.5)..controls (2.29114,0.98723) and (3.72412,0.97192) ..(5,1.5)..controls (5.68967,1.78545) and (6.30771,2.22081) ..(7,2.5)..controls (8.58867,3.1407) and (10.3946,2.90645) ..(12,3.5)..controls (12.3506,3.62962) and (12.68594,3.7973) ..(13,4) {(unknown path p~9)=(path)} {addto} {addto} ! A primary expression can't begin with `doublepath'. 0 doublepath l.85 addto doublepath (-4095,0)..tension I'm afraid I need some sort of value in order to continue, so I've tentatively inserted `0'. You may want to delete this zero and insert something else; see Chapter 27 of The METAFONTbook for an example. >> 0 ! Not a suitable variable. doublepath l.85 addto doublepath (-4095,0)..tension At this point I needed to see the name of a picture variable. (Or perhaps you have indeed presented me with one; I might have missed it, if it wasn't followed by the proper token.) So I'll not change anything just now. ! Extra tokens will be flushed. doublepath l.85 addto doublepath (-4095,0)..tension I've just read as much of that statement as I could fathom, so a semicolon should have been next. It's very puzzling... but I'll try to get myself back together, by ignoring everything up to the next `;'. Please insert a semicolon now in front of anything that you don't want me to delete. (See Chapter 27 of The METAFONTbook for an example.) {show} {-(90)} {(picture)rotated(-90)} >> Edge structure at line 86: Filled pen stroke : (0,-0.5)..controls (0.5,-1.5) and (1,-2.5) ..(1.5,-3.5) dashed (on 3 off 0) shifted 0 butt ends, mitered joins limited 1 with pen pencircle transformed (0,0,0,0,0,0) Filled pen stroke : (0,0)..controls (0.20053,-0.3153) and (0.36807,-0.6504) ..(0.5,-1)..controls (0.98723,-2.29114) and (0.97192,-3.72412) ..(1.5,-5)..controls (1.78545,-5.68967) and (2.22081,-6.30771) ..(2.5,-7)..controls (3.1407,-8.58867) and (2.90645,-10.3946) ..(3.5,-12)..controls (3.62962,-12.3506) and (3.7973,-12.68594) ..(4,-13) butt ends, mitered joins limited 1 with pen pencircle transformed (0,0,0,0,0,0) End edges {if} {if} {elseif} ! Missing `:' has been inserted. : elseif l.87 if "a" if "ab">"b" elseif path reverse (3,4): >="aa":foo... {("ab")>("b")} {false} {reverse((3,4))} {path(path)} {true} {("a")>=("aa")} {false} {if} {((xpart ',ypart '))-((1,yy))} {((xpart '-1,linearform))<((xpart ',ypart '))} {true} {fi} {else} ! Extra else. l.88 ... if '-(1,yy)<': :fi else def dup text t=[[t;save endd... I'm ignoring this; it doesn't match any if. {def} {def} {def} ||->show.substring(EXPR0)of("a" (EXPR0)<-(2,-1) {show} {("a")&("bc")} {((2,-1))substring("abc")} >> "ba" {tertiarydef} {def} {show} {((23.3,4.5))subpath(path)} Path at line 95, before choices: (0,0){curl 2} ..(13,4)..controls (12.84297,3.89865) and (12.68063,3.80606) ..(12.51372,3.72261){curl 3} ..{curl 4}(-1,-1){curl 4} ..{curl 2}cycle Path at line 95, after choices: (0,0)..controls (-40.15552,-36.7088) and (58.71173,33.50317) ..(13,4)..controls (12.84297,3.89865) and (12.68063,3.80606) ..(12.51372,3.72261)..controls (8.00914,2.1484) and (3.50458,0.5742) ..(-1,-1)..controls (-0.66667,-0.66667) and (-0.33333,-0.33333) ..cycle >> Path at line 95: (0,0)..controls (-40.15552,-36.7088) and (58.71173,33.50317) ..(13,4)..controls (12.84297,3.89865) and (12.68063,3.80606) ..(12.51372,3.72261)..controls (8.00914,2.1484) and (3.50458,0.5742) ..(-1,-1)..controls (-0.66667,-0.66667) and (-0.33333,-0.33333) ..cycle {(2)+(3)} ++->[[dup.showtoken(EXPR0);]];def.x.expr.z.of(EXPR1)=z.enddef;texts(x=(( EXPR1)+0)(EXPR1)+(EXPR1))("xx",foo((EXPR0)))=0]] (EXPR0)<-path (EXPR1)<-5 {begingroup} dup->[[(TEXT0);save (TEXT0)<-showtoken(path) {begingroup} {showtoken} > (path) {save} {restoring ;} {endgroup} {def} ! Missing symbolic token inserted. INACCESSIBLE ++->...]];def.x.expr.z.of(EXPR1) =z.enddef;texts(x=((EXPR1)+0)... ; l.95 ...rl4}..cycle;zzz=p~++2+3; [[ Sorry: You can't redefine a number, string, or expr. I've inserted an inaccessible symbol so that your definition will be completed without mixing me up too badly. texts(TEXT0)(TEXT1)->for.n:=,for.n"yy":n,length.if.false:endfor(TE XT1),(TEXT0),:if.string.n:forsuffixes.n=foo1,[foo(n)],':show(TEXT0),(TEX T1)|(n;exitif.not('<='+((EXPR2),yy))endfor.for.m= :+endfor.for.m=alpha.s tep-1.1 3$:+m.endfor.fi.endfor (TEXT0)<-x=((5)+0)(5)+(5) (TEXT1)<-"xx",foo((path)) (EXPR2)<-0 {for} {for} ! Missing `=' has been inserted. "yy" texts->for.n:=,for.n"yy" :n,length.if.false:endfor(TEXT1),(TEX... ]] ; l.95 ...rl4}..cycle;zzz=p~++2+3; [[ The next thing in this loop should have been `=' or `:='. But don't worry; I'll pretend that an equals sign was present, and I'll look for the values next. {loop value="yy"} {if} {false} {false} ! Incomplete if; all text was ignored after line 95. fi ENDFOR ....if.false: ENDFOR texts->...length.if.false:endfor (TEXT1),(TEXT0),:if.string.n:... ]] ; l.95 ...rl4}..cycle;zzz=p~++2+3; [[ A forbidden `outer' token occurred in skipped text. This kind of error happens when you say `if...' and forget the matching `fi'. I've inserted a `fi'; this might work. {[repeat the loop]} {length("xx")} foo(TEXT2)->begingroup(TEXT2)endgroup (SUFFIX0)<- (SUFFIX1)<-foo (TEXT2)<-(path) {begingroup} {endgroup} xof->(EXPR0) {(5)+(0)} (EXPR0)<-5 ! Missing `of' has been inserted for x. (5) x=((5)+0)(5) +(5) texts->...:endfor(TEXT1),(TEXT0) ,:if.string.n:forsuffixes.n=f... ]] ; l.95 ...rl4}..cycle;zzz=p~++2+3; [[ I've got the first argument; will look now for the other. (EXPR1)<-5 {(5)+(5)} {loop value="yy"} {if} {string("yy")} {true} {forsuffixes} ! Missing symbolic token inserted. INACCESSIBLE ...orsuffixes(EXPR0) =foo1,[foo((EXPR0))],':show.x... texts->...3$:+m.endfor.fi.endfor ]] ; l.95 ...rl4}..cycle;zzz=p~++2+3; [[ Sorry: You can't redefine a number, string, or expr. I've inserted an inaccessible symbol so that your definition will be completed without mixing me up too badly. foo(TEXT2)->begingroup(TEXT2)endgroup (SUFFIX0)<- (SUFFIX1)<-foo (TEXT2)<-("yy") {begingroup} {endgroup} >> "yy" ! Improper subscript has been replaced by zero. ...o1,[foo((EXPR0))] ,':show.x=((5)+0)(5)+(5),"xx"... texts->...3$:+m.endfor.fi.endfor ]] ; l.95 ...rl4}..cycle;zzz=p~++2+3; [[ A bracketed subscript must have a known numeric value; unfortunately, what I found was the value that appears just above this error message. So I'll try a zero subscript. {loop value=foo1} {show} xof->(EXPR0) {(5)+(0)} (EXPR0)<-5 ! Missing `of' has been inserted for x. (5) show.x=((5)+0)(5) +(5),"xx",foo((path))|(("yy");ex... ...'+((0),yy))endfor .for.m= :+endfor.for.m=alpha.... texts->...3$:+m.endfor.fi.endfor ]] ; l.95 ...rl4}..cycle;zzz=p~++2+3; [[ I've got the first argument; will look now for the other. (EXPR1)<-5 {(5)+(5)} >> 10 >> "xx" foo(TEXT2)->begingroup(TEXT2)endgroup (SUFFIX0)<- (SUFFIX1)<-foo (TEXT2)<-(path) {begingroup} {endgroup} |->,(SUFFIX0) ! Missing `)' has been inserted. ("yy") ...o((path))|(("yy") ;exitif.not('<='+((0),yy)) EN... ...'+((0),yy))endfor .for.m= :+endfor.for.m=alpha.... texts->...3$:+m.endfor.fi.endfor ]] ; l.95 ...rl4}..cycle;zzz=p~++2+3; [[ I've gotten to the end of the macro parameter list. You might want to delete some tokens before continuing. (SUFFIX0)<- >> Path at line 95: (0,0)..controls (15,4) and (-15,-12) ..(4,0) >> "yy" {exitif} {((xpart ',ypart '))+((0,yy))} {((xpart ',ypart '))<=((xpart ',linearform))} >> -yy ! Unknown relation will be considered false. ) ...ot('<='+((0),yy)) ENDFOR ...'+((0),yy))endfor .for.m= :+endfor.for.m=alpha.... texts->...3$:+m.endfor.fi.endfor ]] ; l.95 ...rl4}..cycle;zzz=p~++2+3; [[ Oh dear. I can't decide if the expression above is positive, negative, or zero. So this comparison test won't be `true'. {[repeat the loop]} {loop value=0} {not(false)} {true} {for} {for} >> 0.5p3~ ! Improper initial value has been replaced by 0. step ....for.m=alpha.step -1.1 3$:+m.endfor.fi ENDFOR texts->...3$:+m.endfor.fi.endfor ]] ; l.95 ...rl4}..cycle;zzz=p~++2+3; [[ When you say `for x=a step b until c', the initial value `a' and the step size `b' and the final value `c' must have known numeric values. I'm zeroing this one. Proceed, with fingers crossed. {-(1.1)} ! Missing `until' has been inserted. 3 ...=alpha.step-1.1 3 $:+m.endfor.fi ENDFOR texts->...3$:+m.endfor.fi.endfor ]] ; l.95 ...rl4}..cycle;zzz=p~++2+3; [[ I assume you meant to say `until' after `step'. So I'll look for the final value and colon next. {(3)*(-1)} {loop value=0} {[repeat the loop]} {loop value=-1.1} {+(0)} {[repeat the loop]} {loop value=-2.20001} {(0)+(-1.1)} {[repeat the loop]} {fi} {[repeat the loop]} {loop value=2} {if} {string(2)} {false} {[repeat the loop]} {loop value=path} {if} {string(path)} {false} {[repeat the loop]} {loop value=10} {if} {string(10)} {false} {[repeat the loop]} {(-1.1)+(-2.20001)} {endgroup} {(zzz)=(-3.30002)} ## zzz=-3.30002 {begingroup} {let} {save} {def} {def} texts->input {input} (trap.mp if->endinput? {endinput} {if} {known(0)} {not(true)} {false} ) ! Incomplete if; all text was ignored after line 2. fi l.96 ...=input enddef;texts trap ]]; The file ended while I was skipping conditional text. This kind of error happens when you say `if...' and forget the matching `fi'. I've inserted a `fi'; this might work. {restoring \} {restoring if} {endgroup} dup->[[(TEXT0);save Runaway text? [[def.texts.secondary.x=primarydef.y++y=x@y.enddef;showtoken ETC. ! Forbidden token found while scanning a text argument. endgroup \ l.97 ... showtoken++;x enddef]]\ ; It seems that a right delimiter was left out, causing me to read past where you wanted me to stop. I'll try to recover; but if the error is serious, you'd better type `E' or `X' now and fix your file. (TEXT0)<-[[def.texts.secondary.x=primarydef.y++y=x@y.enddef;showtoken++; x.enddef]] {begingroup} {begingroup} {def} {endgroup} {save} ! Missing symbolic token inserted. INACCESSIBLE \ l.97 ... showtoken++;x enddef]]\ ; Sorry: You can't redefine my error-recovery tokens. I've inserted an inaccessible symbol so that your definition will be completed without mixing me up too badly. {\} texts->primarydef.y++y=(EXPR0)@y.enddef;showtoken++;(EXPR0) (EXPR0)<-"a" {primarydef} {showtoken} > ++=primarydef'd macro: ("a")@(EXPR1) {("a")&("b")} ab texts->primarydef.y++y=(EXPR0)@y.enddef;showtoken++;(EXPR0) {(1.00002)*(a1)} {-(1.00002a1)} (EXPR0)<--1.00002a1 {primarydef} {showtoken} > ++=primarydef'd macro: (-1.00002a1)@(EXPR1) {(a2)+(a3)} {(linearform)+(a4)} {(linearform)+(a5)} {(linearform)+(a6)} {-(linearform)} {(-1.00002a1)=(linearform)} ## a1=0.99998a6+0.99998a5+0.99998a4+0.99998a3+0.99998a2 {-((a3,a2))} {((-a3,-a2))/(0.99998)} {(a4)+(a5)} {begingroup} {showdependencies} a1=0.99998a6+0.99998a5+0.99998a4+0.99998a3+0.99998a2 alpha=0.5p3~ {endgroup} {(linearform)+(a6)} {(a3)+(a4)} {(linearform)+(a5)} {(linearform)+(a6)} {-((linearform,linearform))} {((-1.00002a3,-1.00002a2))=((linearform,linearform))} ## a2=0.99998a6+0.99998a5+0.99998a4+0.99998a3 ## a3=0.99998a6+0.99998a5+0.99998a4 {restoring INACCESSIBLE} {endgroup} {(1.00002)*(0.25a4*4)} {(0.25a4*4)+(1)} {(0.25a5*4)+(0.25a6*4)} {(0.25a4*4+1)=(linearform)} ## a4*4=0.99998a6*4+0.99998a5*4-3.99994 {(0.9)*(0.5p3~)} {(0.45p3~)+(7)} {alpha:=0.45p3~+7} ## alpha=0.45p3~+7 {showdependencies} alpha=0.45p3~+7 a4=0.25a6*4+0.25a5*4-0.99998 a3=0.49998a6*4+0.49998a5*4-0.99997 a2=0.99997a6*4+0.99997a5*4-1.99992 a1=1.99992a6*4+1.99992a5*4-3.99982 {(0.66667)-(0.25a6*4)} {(0.25a6*4)=(-0.25a6*4+0.66667)} ## a6*4=1.33334 {(0.25a5*4)=(0.33333)} ## a5*4=1.33331 #### a4=-0.33333 #### a3=0.33333 #### a2=0.66664 #### a1=1.33328 {chardp:=27} {charcode:=27} {(3.1)=(aaz)} ## aaz=3.1 {show} >> 3.1 {ligtable} {show} {begingroup} {interim} {tracingcommands:=0} lig(TEXT0)(TEXT1)->ligtable0::for*=1step1until60:0kern.boundarychar+*,en dfor.skipto0;ligtable(TEXT0):(TEXT0)(TEXT1)0,skipto255;boundarychar:=bou ndarychar+51.29999 (TEXT0)<-"g" (TEXT1)<-=:| lig(TEXT0)(TEXT1)->ligtable0::for*=1step1until60:0kern.boundarychar+*,en dfor.skipto0;ligtable(TEXT0):(TEXT0)(TEXT1)0,skipto255;boundarychar:=bou ndarychar+51.29999 (TEXT0)<-"h":"i" (TEXT1)<-|=: ! Character h is already in a ligtable. : "h": "i" lig->...;ligtable(TEXT0):(TEXT0) (TEXT1)0,skipto255;boundarych... l.102 ...=:|); lig("h":"i")(|=:) ; It's not legal to label a character more than once. So I'll not change anything just now. lig(TEXT0)(TEXT1)->ligtable0::for*=1step1until60:0kern.boundarychar+*,en dfor.skipto0;ligtable(TEXT0):(TEXT0)(TEXT1)0,skipto255;boundarychar:=bou ndarychar+51.29999 (TEXT0)<-"j" (TEXT1)<-|=:> lig(TEXT0)(TEXT1)->ligtable0::for*=1step1until60:0kern.boundarychar+*,en dfor.skipto0;ligtable(TEXT0):(TEXT0)(TEXT1)0,skipto255;boundarychar:=bou ndarychar+51.29999 (TEXT0)<-"k" (TEXT1)<-=:|> lig(TEXT0)(TEXT1)->ligtable0::for*=1step1until60:0kern.boundarychar+*,en dfor.skipto0;ligtable(TEXT0):(TEXT0)(TEXT1)0,skipto255;boundarychar:=bou ndarychar+51.29999 (TEXT0)<-"l" (TEXT1)<-|=:|> {restoring tracingcommands=2.1} {endgroup} >> vacuous {begingroup} {let} {vardef} {endgroup} ! Variable c.a1 has been obliterated. ; l.104 ...;vardef b=enddef;1]] ]; ligtable"m":0=:0,skipto5; It seems you did a nasty thing---probably by accident, but nevertheless you nearly hornswoggled me... While I was evaluating the suffix of this variable, something was redefined, and it's no longer a variable! In order to get back on my feet, I've inserted `0' instead. {b1:=0} ! Variable b1 has been obliterated. ; l.104 ...;vardef b=enddef;1]] ]; ligtable"m":0=:0,skipto5; It seems you did a nasty thing---probably by accident, but nevertheless you nearly hornswoggled me... While I was evaluating the right-hand side of this command, something happened, and the left-hand side is no longer a variable! So I won't change anything. {ligtable} ! A statement can't begin with `skipto'. !! l.105 !! ; errhelp 0; errmessage "Be like Jane"; I was looking for the beginning of a new statement. If you just proceed without changing anything, I'll ignore everything up to the next `;'. Please insert a semicolon now in front of anything that you don't want me to delete. (See Chapter 27 of The METAFONTbook for an example.) ! Extra tokens will be flushed. !! l.105 !! ; errhelp 0; errmessage "Be like Jane"; I've just read as much of that statement as I could fathom, so a semicolon should have been next. It's very puzzling... but I'll try to get myself back together, by ignoring everything up to the next `;'. Please insert a semicolon now in front of anything that you don't want me to delete. (See Chapter 27 of The METAFONTbook for an example.) {errhelp} >> 0 ! Not a string. ; l.105 !!; errhelp 0; errmessage "Be like Jane"; A message should be a known string expression. {errmessage} ! Be like Jane. ; l.105 ...message "Be like Jane"; This error message was generated by an `errmessage' command, so I can't give any explicit help. Pretend that you're Miss Marple: Examine all clues, and deduce the truth by inspired guesses. {errhelp} {errmessage} ! . ; l.106 ...e%%%lp%"; errmessage""; errhelp ""; errmessage "Anot... He% lp {errhelp} {errmessage} ! Another. ; l.106 ...; errmessage "Another"; (That was another `errmessage'.) {headerbyte} >> 0 ! Improper location. ; l.107 headerbyte 0; headerbyte(48.5)substring(-9,9)of"long"; ... I was looking for a known, positive number. For safety's sake I'll ignore the present command. {headerbyte} ! Missing `:' has been inserted. substring l.107 ...aderbyte(48.5)substring (-9,9)of"long"; for\=0:\ A colon should follow a headerbyte or fontinfo location. {-(9)} {((-9,9))substring("long")} >> "long" ! Invalid code has been replaced by 0. ; l.107 ...ubstring(-9,9)of"long"; for\=0:\ I was looking for a number between 0 and 255, or for a string of length 1. Didn't find it; will use 0 instead. {for} Runaway loop? ! Forbidden token found while scanning the text of a for loop. endfor \ l.107 ...-9,9)of"long"; for\=0:\ I suspect you have forgotten an `endfor', causing me to read past where you wanted me to stop. I'll try to recover; but if the error is serious, you'd better type `E' or `X' now and fix your file. {loop value=0} {[repeat the loop]} {\} {headerbyte} {(2)*(0.33333)} {fontdimen} {(2)*(0.33333)} >> "q" ! Improper font parameter. ; l.108 ..."; fontdimen 9:2a6,"q"; fontdimen 1:2048; I'm zeroing this one. Proceed, with fingers crossed. {fontdimen} {fontmaking:=1} {extensible} ! Missing `:' has been inserted. 5 l.109 ...king:=1; extensible 5 5 ,"c"255.5,"d"; charlist 0:5:"... I'm processing `extensible c: t,m,b,r'. ! Missing `,' has been inserted. 255.5 l.109 ...extensible 5 5,"c"255.5 ,"d"; charlist 0:5:"a":"d"; I'm processing `extensible c: t,m,b,r'. >> 255.5 ! Invalid code has been replaced by 0. , l.109 ...xtensible 5 5,"c"255.5, "d"; charlist 0:5:"a":"d"; I was looking for a number between 0 and 255, or for a string of length 1. Didn't find it; will use 0 instead. {charlist} ! Character code 5 is already extensible. : l.109 ...,"d"; charlist 0:5:"a": "d"; It's not legal to label a character more than once. So I'll not change anything just now. {ligtable} ! Too far to skip. l.110 ligtable255:255:: "a"=:"b","d" kern -2048,"c":0:99.5:"e"... At most 127 lig/kern steps can separate skipto1 from 1::. {-(2048)} ! Character code 0 is already in a charlist. : l.110 ...","d" kern -2048,"c":0: 99.5:"e"|=:|"f",0kern'; It's not legal to label a character more than once. So I'll not change anything just now. >> (xpart ',ypart ') ! Improper kern. ; l.110 ...99.5:"e"|=:|"f",0kern'; The amount of kern should be a known numeric value. I'm zeroing this one. Proceed, with fingers crossed. {ligtable} ! Character code 5 is already extensible. : l.111 ligtable 5: 0; def clear(text x)=interim x:=$ enddef; cl... It's not legal to label a character more than once. So I'll not change anything just now. ! Illegal ligtable step. ; l.111 ligtable 5:0; def clear(text x)=interim x:=$ enddef; cl... I was looking for `=:' or `kern' here. {def} clear(TEXT0)->interim(TEXT0):=$ (TEXT0)<-hppp {interim} ! The token `hppp' isn't an internal quantity. hppp clear->interim(TEXT0) :=$ l.111 ...:=$ enddef; clear(hppp) ; vppp=0; Something like `tracingonline' should follow `interim'. {hppp:=-1} ## hppp=-1 {(vppp)=(0)} ## vppp=0 {begingroup} clear(TEXT0)->interim(TEXT0):=$ (TEXT0)<-tracingmacros {interim} {tracingmacros:=-1} {interim} {tracingcommands:=-1} Runaway text? tracingoutput ! Forbidden token found while scanning a text argument. ) \ l.112 ...); clear(tracingoutput\ ; It seems that a right delimiter was left out, causing me to read past where you wanted me to stop. I'll try to recover; but if the error is serious, you'd better type `E' or `X' now and fix your file. [95] [96] [97] [98] [99] [100] [101] [102] [103] [104] [105] [106] [107] ## chardy=6 [108] [109] {restoring tracingoutput=1} {restoring tracingcommands=2.1} {restoring tracingmacros=1} {endgroup} {def} {def} {addto} Path at line 122, before choices: (0,0){4096,0} ..{4096,0}(1,0){0,-4096} ..{0,4096}cycle Path at line 122, after choices: (0,0)..controls (0.33333,0) and (0.66667,0) ..(1,0)..controls (1,-0.66667) and (0,-0.66667) ..cycle f(SUFFIX0)(EXPR1)(EXPR2)(TEXT3)->numeric.w;show(EXPR1);addto(SUFFIX0)con tour(0,0)..(2,0)..(1,$)..(1,1)..cycle.withpen.qq;addto(SUFFIX0)doublepat h(0,0){1,1}..{2,1}(2,1)withpen.qq;addto(SUFFIX0)doublepath(($,$){1,0}..( 1,1){1,0})scaled0.5withpen.nullpen; ! Missing `]' has been inserted. , l.123 f(e[3, w); g(e3,transformed p,penoffset-(1,1.3)of(pencir... I've seen a `[' and a subscript value, in a suffix, so a right bracket should have come next. I shall pretend that one was there. (SUFFIX0)<-e3 (EXPR1)<-unknown path w ! Missing argument to f. ; l.123 f(e[3,w); g(e3,transformed p,penoffset-(1,1.3)of(pencir... That macro has more parameters than you thought. I'll continue by pretending that each missing argument is either zero or null. (EXPR2)<-0 ! Missing argument to f. ; l.123 f(e[3,w); g(e3,transformed p,penoffset-(1,1.3)of(pencir... That macro has more parameters than you thought. I'll continue by pretending that each missing argument is either zero or null. (TEXT3)<- {numeric} {show} >> unknown path %CAPSULE1695 {addto} Path at line 123, before choices: (0,0) ..(2,0) ..(1,-1) ..(1,1) ..cycle Path at line 123, after choices: (0,0)..controls (0.56189,-0.5286) and (1.43811,0.5286) ..(2,0)..controls (2.70831,-0.66634) and (1.66634,-1.70831) ..(1,-1)..controls (0.4714,-0.43811) and (1.5286,0.43811) ..(1,1)..controls (0.33366,1.70831) and (-0.70831,0.66634) ..cycle {addto} Path at line 123, before choices: (0,0){2896.30943,2896.30934} ..{3663.57385,1831.78674}(2,1) Path at line 123, after choices: (0,0)..controls (0.53566,0.53566) and (1.32689,0.66344) ..(2,1) {addto} Path at line 123, before choices: (-1,-1){4096,0} ..{4096,0}(1,1) Path at line 123, after choices: (-1,-1)..controls (0.10457,-1) and (-0.10457,1) ..(1,1) {(path)scaled(0.5)} {nullpen} g(SUFFIX0)->show(SUFFIX0) (SUFFIX0)<-e3 ! Too many arguments to g; Missing `)' has been inserted. l.123 f(e[3,w); g(e3, transformed p,penoffset-(1,1.3)of(pencir... I'm going to assume that the comma I just read was a right delimiter, and then I'll begin expanding the macro. You might want to delete some tokens before continuing. {show} {(picture)transformed((8,1,5,-5,-5,5))} >> Edge structure at line 123: Filled pen stroke : (10.5,-1.5)..controls (13,-4) and (15.5,-6.5) ..(18,-9) dashed (on 0 off 0) shifted 0 butt ends, mitered joins limited 1 with pen pencircle transformed (0,0,0,0,0,0) Filled pen stroke : (8,1)..controls (8.57388,0.42612) and (9.41167,-0.41167) ..(10.5,-1.5)..controls (14.51955,-5.51955) and (21.76099,-12.76099) ..(25.5,-16.5)..controls (27.5211,-18.5211) and (28.4345,-19.4345) ..(30.5,-21.5)..controls (35.23984,-26.23984) and (45.4408,-36.4408) ..(50.5,-41.5)..controls (51.60489,-42.60489) and (52.4432,-43.4432) ..(53,-44) butt ends, mitered joins limited 1 with pen pencircle transformed (0,0,0,0,0,0) Filled contour : (8,1)..controls (13.45242,-4.45242) and (12.54758,-3.54758) ..(18,-9)..controls (24.87325,-15.87325) and (24.87325,-15.87325) ..(18,-9)..controls (12.54758,-3.54758) and (13.45242,-4.45242) ..(8,1)..controls (1.12675,7.87325) and (1.12675,7.87325) ..cycle mitered joins limited 1 with pen (-10,10) .. (5,-5) .. (12.5,-12.5) .. (15,-15) .. (15,-15) .. (10,-10) .. (-5,5) .. (-12.5,12.5) .. (-15,15) .. (-15,15) .. cycle Filled pen stroke : (8,1)..controls (8,1) and (11.31726,-2.31726) ..(13,-4) butt ends, mitered joins limited 1 with pen (-10,10) .. (5,-5) .. (12.5,-12.5) .. (15,-15) .. (15,-15) .. (10,-10) .. (-5,5) .. (-12.5,12.5) .. (-15,15) .. (-15,15) .. cycle Filled pen stroke : (8,1)..controls (10.76146,-1.76146) and (5.23854,3.76146) ..(8,1) butt ends, mitered joins limited 1 with pen pencircle transformed (0,0,0,0,0,0) End edges {-((1,1.3))} {pencircle} {(pen)scaled(20)} {-(0.5)} {(pen)yscaled(-0.5)} {((-1,-1.3))penoffset(pen)} >> (-9.33345,1.79489) Path at line 124, before choices: (0,0)..controls (1,1) and (-1,1) ..(3,0) Path at line 124, after choices: (0,0)..controls (1,1) and (-1,1) ..(3,0) {((0,1))directiontime(path)} >> 0.33333 {(3.14159)point(path)} {((3.14159,4))subpath(path)} {((7.68668,2.72437))intersectiontimes(path)} >> (0,0) Path at line 126, before choices: (-1,1.1){curl 1} ..{curl 1}(1,-1) Path at line 126, after choices: (-1,1.1)..controls (-0.33333,0.40001) and (0.33333,-0.3) ..(1,-1) {(-1)precontrol((0,0))} {(path)intersectiontimes((0,0))} >> (-1,-1) {addto} {-(4094.99998)} {-(0.00002)} Path at line 127, before choices: (-4094.99998,0){curl 1} ..{curl 1}(4094.99998,-0.00002) Path at line 127, after choices: (-4094.99998,0)..controls (-1365,0) and (1365,-0.00002) ..(4094.99998,-0.00002) {pencircle} {(0)penoffset(pen)} >> 0 >> pen ! Not implemented: penoffset(known numeric)of(pen). ; l.128 pencircle; addto e3 also e3 shifted (0,257); ,"flushed ... I'm afraid I don't know how to apply that operation to that combination of types. Continue, and I'll return the second argument (see above) as the result of the operation. {addto} {(picture)shifted((0,257))} ! A statement can't begin with `,'. , l.128 ...o e3 shifted (0,257); , "flushed with pride"; numeric... I was looking for the beginning of a new statement. If you just proceed without changing anything, I'll ignore everything up to the next `;'. Please insert a semicolon now in front of anything that you don't want me to delete. (See Chapter 27 of The METAFONTbook for an example.) ! Extra tokens will be flushed. , l.128 ...o e3 shifted (0,257); , "flushed with pride"; numeric... I've just read as much of that statement as I could fathom, so a semicolon should have been next. It's very puzzling... but I'll try to get myself back together, by ignoring everything up to the next `;'. Please insert a semicolon now in front of anything that you don't want me to delete. (See Chapter 27 of The METAFONTbook for an example.) {numeric} {def} f(EXPR0)(EXPR1)(EXPR2)->showdependencies;tracingcapsules:=1;showdependen cies;show1/3(3,6)*(((EXPR0)+(EXPR1))+((EXPR1)-(EXPR0))),(1,1)/sqrt2zscal ed((EXPR0)+1,(EXPR0)+2)-((EXPR0)+1,(EXPR0)+2)rotated45,(0,1)zscaled(1,(E XPR1)+2)-(1,(EXPR1)+2)rotated90 {(xx)+(1)} {(xx+1)/(0.3)} (EXPR0)<-3.3333xx+3.3333 {(yy)-(1)} {(yy-1)/(0.5)} (EXPR1)<-2yy-2 (EXPR2)<-(xx,0) {showdependencies} alpha=0.45p3~+7 {tracingcapsules:=1} {showdependencies} xpart %CAPSULE2512=xx %CAPSULE2520=2yy-2 %CAPSULE2528 = 3.3333xx+3.3333 alpha=0.45p3~+7 {show} {(1/3)*((3,6))} {(3.3333xx+3.3333)+(2yy-2)} {(2yy-2)-(3.3333xx+3.3333)} {(linearform)+(linearform)} {((1,2))*(4yy-4)} >> (4yy-4,8yy-8) {sqrt(2)} {((1,1))/(1.41422)} {(3.3333xx+3.3333)+(1)} {(3.3333xx+3.3333)+(2)} {((0.7071,0.7071))zscaled((3.3333xx+4.3333,3.3333xx+5.3333))} {(3.3333xx+3.3333)+(1)} {(3.3333xx+3.3333)+(2)} {((3.3333xx+4.3333,3.3333xx+5.3333))rotated(45)} {((-0.7071,4.71399xx+6.83531))-((-0.7071,4.71399xx+6.83531))} >> (0,0) {(2yy-2)+(2)} {((0,1))zscaled((1,2yy))} {(2yy-2)+(2)} {((1,2yy))rotated(90)} {((-2yy,1))-((-2yy,1))} >> (0,0) {(1000)*(o3)} {(o1)-(o2)} {(4000)*(linearform)} {(1000o3)-(linearform)} {(4000)*(o2)} {(linearform)+(4000o2)} {(linearform)+(9)} {(0.01)*(o3)} {-(0.01o3)} {(3)*(ooo)} {(-0.01o3)+(3ooo)} {begingroup} {(o2)+(o4)} {(linearform)+(o5)} {(linearform)-(20)} {(9/10)*(linearform)} {(oo)=(linearform)} ## oo=0.9o5+0.9o4+0.9o2-18 {(0.5)*(o2)} {(o1)+(0.5o2)} {(8/9)*(linearform)} {(o5)=(linearform)} ## o5=0.44444o2+0.88889o1 {(o4)=(linearform)} ## o4=0.44444o2+0.88889o1 {(0.0001)*(o2)} {-(0.0001o2)} {(o6)=(-0.0001o2)} ## o6=-0.0001o2 {showdependencies} o6=-0.0001o2 o4=0.44444o2+0.88889o1 o5=0.44444o2+0.88889o1 oo=1.7o2+1.6o1-18 %CAPSULE2440 = 3ooo-0.01o3 %CAPSULE2460 = 8000o2-4000o1+1000o3+9 xpart %CAPSULE2536=xpart ' ypart %CAPSULE2536=ypart ' alpha=0.45p3~+7 {numeric} ### 4000o1 = -%CAPSULE2460+8000o2+1000o3+9 ### -4.87383o2 = -oo-0.0004%CAPSULE2460+0.39673o3-17.99643 #### o6=-0.00027 ### -0.04366o3 = -o4+0.46689oo+8.40439 ### -o4 = -o5 ### 0.22894o5 = -%CAPSULE2440+0.10689oo+3ooo+1.92412 {begingroup} {pair} ### -alfa=-%CAPSULE2428 {endgroup} ### -%CAPSULE2428=-xpart %CAPSULE2426 {xpart((xpart %CAPSULE2426,0))} ### -xpart %CAPSULE9=-%CAPSULE2416 {endgroup} {(%CAPSULE2440)+(%CAPSULE2416)} ### -%CAPSULE2440=-%CAPSULE2404+%CAPSULE2416 ### -%CAPSULE2404=-ypart %CAPSULE2402 ### -%CAPSULE2460=-xpart %CAPSULE2402 {begingroup} {save} {(1)-(p$)} {restoring p} ### p$=-ypart %CAPSULE2368+1 {endgroup} {(2/3)*((-ypart %CAPSULE2368+1,ypart %CAPSULE2368))} ### ypart %CAPSULE2368=-xpart %CAPSULE2368+1 ### -0.66667xpart %CAPSULE2368=-xpart %CAPSULE2360 {-((xpart %CAPSULE2360,-xpart %CAPSULE2360+0.66667))} ### xpart %CAPSULE2360=-xpart %CAPSULE2340 {((xpart %CAPSULE2402,ypart %CAPSULE2402))=((xpart %CAPSULE2340,-xpart % CAPSULE2340-0.66667))} ## xpart %CAPSULE2340=-ypart %CAPSULE2402-0.66667 ## xpart %CAPSULE2402=-ypart %CAPSULE2402-0.66667 ### ypart %CAPSULE2402=-xpart %CAPSULE2402-0.66667 ### -xpart %CAPSULE2402=-xpart %CAPSULE2340 {((xpart ',ypart '))=((xpart %CAPSULE2340,-xpart %CAPSULE2340-0.66667))} ## xpart %CAPSULE2340=-ypart '-0.66667 ## xpart '=-ypart '-0.66667 {begingroup} {(0.5)*(ooo)} {begingroup} {numeric} ### -ooo=-%CAPSULE2302 {endgroup} {(%CAPSULE2302)+(1)} ### -%CAPSULE2302=-%CAPSULE2290+1 {(1/2)*(%CAPSULE2290)} ### -0.5%CAPSULE2290=-%CAPSULE2282 {-(%CAPSULE2282)} ### %CAPSULE2282=-%CAPSULE2274 {(2)*(%CAPSULE2274)} ### -2%CAPSULE2274=-%CAPSULE2266 {(-0.5%CAPSULE2266-0.5)=(%CAPSULE2266)} ## %CAPSULE2266=-0.33333 {(oo)=(-0.33333)} ## oo=-0.33333 {endgroup} {(4000)*(-0.33333)} {yoffset:=-1333.31299} ## yoffset=-1333.31299 {xoffset:=-1333.31299} ## xoffset=-1333.31299 {addto} foo(TEXT2)->begingroup(TEXT2)endgroup (SUFFIX0)<- (SUFFIX1)<-foo ! Missing argument to foo. contour l.136 addto foo contour begingroup vardef foo=enddef; (0,0)..... That macro has more parameters than you thought. I'll continue by pretending that each missing argument is either zero or null. (TEXT2)<- {begingroup} {endgroup} >> vacuous ! Not a suitable variable. contour l.136 addto foo contour begingroup vardef foo=enddef; (0,0)..... At this point I needed to see the name of a picture variable. (Or perhaps you have indeed presented me with one; I might have missed it, if it wasn't followed by the proper token.) So I'll not change anything just now. ! Extra tokens will be flushed. contour l.136 addto foo contour begingroup vardef foo=enddef; (0,0)..... I've just read as much of that statement as I could fathom, so a semicolon should have been next. It's very puzzling... but I'll try to get myself back together, by ignoring everything up to the next `;'. Please insert a semicolon now in front of anything that you don't want me to delete. (See Chapter 27 of The METAFONTbook for an example.) Path at line 136, before choices: (0,0) ..cycle Path at line 136, after choices: (0,0)..controls (0,0) and (0,0) ..cycle ! Extra `endgroup'. l.136 ...; (0,0)..cycle endgroup ; I'm not currently working on a `begingroup', so I had better not try to end anything. {(unknown path p~7)=(unknown path p~8)} {-(1)} Path at line 137, before choices: (0,0){-2896.30943,2896.30934} ..{curl 1}(30,0) Path at line 137, after choices: (0,0)..controls (-48.28429,48.28426) and (78.28429,48.28426) ..(30,0) {p~8:=path} {show} >> Path at line 137: (0,0)..controls (-48.28429,48.28426) and (78.28429,48.28426) ..(30,0) {-(1)} {((0,-1))directiontime(path)} >> 0.83456 {show} {((1,0))directiontime(path)} >> -1 {-(1)} {-(1)} ! Missing `}' has been inserted. ) l.139 ...(0,0){1,0}..(0,0){0,-1) ..cycle); I've scanned a direction spec for part of a path, so a right brace should have come next. I shall pretend that one was there. Path at line 139, before choices: (0,0){4096,0} ..{0,-4096}(0,0) Path at line 139, after choices: (0,0)..controls (0,0) and (0,0) ..(0,0) {((1,-1))directiontime(path)} >> 0 ! Extra tokens will be flushed. .. l.139 ...,0){1,0}..(0,0){0,-1).. cycle); I've just read as much of that statement as I could fathom, so a semicolon should have been next. It's very puzzling... but I'll try to get myself back together, by ignoring everything up to the next `;'. Please insert a semicolon now in front of anything that you don't want me to delete. (See Chapter 27 of The METAFONTbook for an example.) {nullpicture} {(unknown picture e4)=(picture)} {(unknown picture e9)=(picture)} {addto} {addto} ! Picture is too complicated to use as a dash pattern. ; l.141 ...ublepath p~8 dashed e4; e9:=nullpicture; When you say `dashed p', every path in p should be monotone in x and there must be no overlapping. This failed so I'll just make it a solid line instead. {nullpicture} {e9:=picture} {nullpicture} {e4:=picture} {addto} Path at line 142, before choices: (1,1){curl 1} ..{curl 1}(4,1) Path at line 142, after choices: (1,1)..controls (2,1) and (3,1) ..(4,1) {addto} {nullpicture} {e9:=picture} {addto} {pencircle} {makepath(pen)} {-(2)} {(picture)scaled(-2)} {show} >> Edge structure at line 144: Filled pen stroke : (1,1)..controls (2,1) and (3,1) ..(4,1) butt ends, mitered joins limited 1 with pen pencircle transformed (0,0,0,0,0,0) Filled pen stroke : (0.5,0)..controls (0.5,0.13261) and (0.44731,0.25978) ..(0.35355,0.35355)..controls (0.25978,0.44731) and (0.13261,0.5) ..(0,0.5)..controls (-0.13261,0.5) and (-0.25978,0.44731) ..(-0.35355,0.35355)..controls (-0.44731,0.25978) and (-0.5,0.13261) ..(-0.5,0)..controls (-0.5,-0.13261) and (-0.44731,-0.25978) ..(-0.35355,-0.35355)..controls (-0.25978,-0.44731) and (-0.13261,-0.5) ..(0,-0.5)..controls (0.13261,-0.5) and (0.25978,-0.44731) ..(0.35355,-0.35355)..controls (0.44731,-0.25978) and (0.5,-0.13261) ..cycle dashed (on 6 off 0) shifted -2 butt ends, mitered joins limited 1 with pen pencircle transformed (0,0,0,0,0,0) End edges {nullpicture} {(unknown picture e5)=(picture)} {e4:=picture} {addto} {-(4)} {-(3)} {-(2)} {-(2.7)} Path at line 145, before choices: (-4,-3){curl 1}..tension 2 ..{curl 1}(-2,-2.7) Path at line 145, after choices: (-4,-3)..controls (-3.66667,-2.95) and (-2.33333,-2.75) ..(-2,-2.7) {addto} {(path)shifted((0,4))} {(path)scaled(3)} {show} {llcorner(picture)} >> (0.5,9.5) {nullpicture} {e6:=picture} {addto} Path at line 149, before choices: (0,0){curl 1} ..{curl 1}(30,0) Path at line 149, after choices: (0,0)..controls (10,0) and (20,0) ..(30,0) {pencircle} {makepath(pen)} >> path ! Improper type. dashed l.150 dashed e5 withpen pencircle scaled2 dashed e5shifted(0,... Next time say `dashed '; I'll ignore the bad `with' clause and look for another. {pencircle} {(pen)scaled(2)} {-(11)} {(picture)shifted((0,-11))} {pencircle} {show} >> Edge structure at line 151: Filled pen stroke : (0,0)..controls (10,0) and (20,0) ..(30,0) dashed (on 2 off 1) shifted -1 butt ends, mitered joins limited 1 with pen pencircle transformed (0,0,1,0,0,1) End edges {def} {(path)rotated(90)} {-(1)} {(path)xscaled(-1)} Path at line 152, before choices: (0,0)..controls (48.28426,-48.28429) and (48.28426,78.28429) ..(0,30) ..cycle Path at line 152, after choices: (0,0)..controls (48.28426,-48.28429) and (48.28426,78.28429) ..(0,30)..controls (-8.28427,21.71573) and (-8.28427,8.28427) ..cycle {p~7:=path} {linecap:=2} {linejoin:=1} {nullpicture} {(picture)=(picture)} ! Redundant or inconsistent equation. ; l.153 e6=nullpicture; addto e6 doublepath p~8 dashed e5 withp... An equation between already-known quantities can't help. But don't worry; continue and I'll just ignore it. {addto} {pencircle} {clip} {addto} {begingroup} {save} {picture} {nullpicture} {(unknown picture _p)=(picture)} {string} {vardef} {(unknown string _n0)=("trapf")} _s(EXPR2)(EXPR3)(EXPR4)(EXPR5)(EXPR6)->begingroup.addto._p.also(EXPR2)in font(EXPR3)scaled(EXPR4)shifted((EXPR5),(EXPR6));endgroup (SUFFIX0)<- (SUFFIX1)<-_s (EXPR2)<-"Aqua" (EXPR3)<-"trapf" (EXPR4)<-1 (EXPR5)<-0 (EXPR6)<-0 {begingroup} {addto} {("Aqua")infont("trapf")} {(picture)scaled(1)} {(picture)shifted((0,0))} {endgroup} {interim} {linecap:=0} {vardef} _r(EXPR2)(EXPR3)->begingroup.addto._p.doublepath(EXPR2)withpen.pencircle .scaled(EXPR3)endgroup (SUFFIX0)<- (SUFFIX1)<-_r {-(3.9851)} Path at line 11, before choices: (8.1693,-3.9851){curl 1} ..{curl 1}(8.1693,15.9402) Path at line 11, after choices: (8.1693,-3.9851)..controls (8.1693,2.65666) and (8.1693,9.29843) ..(8.1693,15.9402) (EXPR2)<-path (EXPR3)<-0.3985 {begingroup} {addto} {pencircle} {(pen)scaled(0.3985)} {endgroup} {(unknown string _n1)=("trapf")} _s(EXPR2)(EXPR3)(EXPR4)(EXPR5)(EXPR6)->begingroup.addto._p.also(EXPR2)in font(EXPR3)scaled(EXPR4)shifted((EXPR5),(EXPR6));endgroup (SUFFIX0)<- (SUFFIX1)<-_s (EXPR2)<-"Brass" (EXPR3)<-"trapf" (EXPR4)<-2 (EXPR5)<-8.3686 (EXPR6)<-0 {begingroup} {addto} {("Brass")infont("trapf")} {(picture)scaled(2)} {(picture)shifted((8.3686,0))} {endgroup} {setbounds} {-(3.9851)} --->{curl1}..{curl1} {-(3.9851)} --->{curl1}..{curl1} --->{curl1}..{curl1} --->{curl1}..{curl1} Path at line 15, before choices: (0,-3.9851){curl 1} ..{curl 1}(18.3313,-3.9851){curl 1} ..{curl 1}(18.3313,15.9402){curl 1} ..{curl 1}(0,15.9402){curl 1} ..{curl 1}cycle Path at line 15, after choices: (0,-3.9851)..controls (6.11043,-3.9851) and (12.22087,-3.9851) ..(18.3313,-3.9851)..controls (18.3313,2.65666) and (18.3313,9.29843) ..(18.3313,15.9402)..controls (12.22087,15.9402) and (6.11043,15.9402) ..(0,15.9402)..controls (0,9.29843) and (0,2.65666) ..cycle {restoring linecap=2} {restoring _n} {restoring _s} {restoring _r} {restoring _p} {endgroup} {-(2)} {(picture)shifted((0,-2))} {addto} Path at line 155, before choices: (1,0){curl 1} ..{curl 1}(2,1) Path at line 155, after choices: (1,0)..controls (1.33333,0.33333) and (1.66667,0.66667) ..(2,1) {addto} {(0.5)*((1,1,1))} {pencircle} {(pen)xscaled(2)} {(pen)rotated(45)} {addto} {begingroup} {save} {picture} {nullpicture} {(unknown picture _p)=(picture)} {string} {vardef} {(unknown string _n0)=("trapf")} _s(EXPR2)(EXPR3)(EXPR4)(EXPR5)(EXPR6)->begingroup.addto._p.also(EXPR2)in font(EXPR3)scaled(EXPR4)shifted((EXPR5),(EXPR6));endgroup (SUFFIX0)<- (SUFFIX1)<-_s (EXPR2)<-"ast" (EXPR3)<-"trapf" (EXPR4)<-1 (EXPR5)<-0 (EXPR6)<-0 {begingroup} {addto} {("ast")infont("trapf")} {(picture)scaled(1)} {(picture)shifted((0,0))} {endgroup} {setbounds} {-(0.9963)} --->{curl1}..{curl1} {-(0.9963)} --->{curl1}..{curl1} --->{curl1}..{curl1} --->{curl1}..{curl1} Path at line 25, before choices: (0,-0.9963){curl 1} ..{curl 1}(1.9925,-0.9963){curl 1} ..{curl 1}(1.9925,6.9738){curl 1} ..{curl 1}(0,6.9738){curl 1} ..{curl 1}cycle Path at line 25, after choices: (0,-0.9963)..controls (0.66417,-0.9963) and (1.32832,-0.9963) ..(1.9925,-0.9963)..controls (1.9925,1.6604) and (1.9925,4.3171) ..(1.9925,6.9738)..controls (1.32832,6.9738) and (0.66417,6.9738) ..(0,6.9738)..controls (0,4.3171) and (0,1.6604) ..cycle {restoring _n} {restoring _s} {restoring _r} {restoring _p} {endgroup} {(picture)shifted((0,10))} {show} >> Edge structure at line 158: clipping path: (0,0)..controls (48.28426,-48.28429) and (48.28426,78.28429) ..(0,30)..controls (-8.28427,21.71573) and (-8.28427,8.28427) ..cycle Filled pen stroke : (0,0)..controls (10,0) and (20,0) ..(30,0) dashed (on 2 off 1) shifted -1 butt ends, mitered joins limited 1 with pen pencircle transformed (0,0,1,0,0,1) Filled pen stroke : (0,0)..controls (-48.28429,48.28426) and (78.28429,48.28426) ..(30,0) dashed (on 1 off 1 on 1 off 9) shifted -9 square ends, round joins with pen pencircle transformed (0,0,1,0,0,1) stop clipping setbounds path: (0,-5.9851)..controls (6.11043,-5.9851) and (12.22087,-5.9851) ..(18.3313,-5.9851)..controls (18.3313,0.65666) and (18.3313,7.29843) ..(18.3313,13.9402)..controls (12.22087,13.9402) and (6.11043,13.9402) ..(0,13.9402)..controls (0,7.29843) and (0,0.65666) ..cycle "Aqua" infont "trapf" transformed (0,-2,1,0,0,1) Filled pen stroke : (8.1693,-5.9851)..controls (8.1693,0.65666) and (8.1693,7.29843) ..(8.1693,13.9402) butt ends, round joins with pen pencircle transformed (0,0,0.3985,0,0,0.3985) "Brass" infont "trapf" transformed (8.3686,-2,2,0,0,2) end of setbounds Filled pen stroke : (1,0)..controls (1.33333,0.33333) and (1.66667,0.66667) ..(2,1) square ends, round joins with pen pencircle transformed (0,0,0,0,0,0) End edges {lrcorner(picture)} >> (36.21318,-5.9851) {ulcorner(picture)} >> (-6.2132,37.00375) {charcode:=200} {shipout} [200 Envelope spec at line 158: (3,12) % beginning with offset (2,-1) ..controls (3.75,12.75) and (4.125,13.3125) ..(4.3125,13.6875) ..controls (4.375,13.8125) and (4.41667,13.91667) ..(4.44444,14) % counterclockwise to offset (2.5,0.5) ..controls (4.5,14.16667) and (4.5,14.25) ..(4.5,14.25) % clockwise to offset (-2.5,-0.5) ..controls (4.5,14.25) and (4.5,13.5) ..(6,12) % counterclockwise to offset (2.5,0.5) ..controls (4.5,13.5) and (4.5,14.25) ..(4.5,14.25) % counterclockwise to offset (-2.5,-0.5) ..controls (4.5,14.25) and (4.5,14.16667) ..(4.44444,14) % clockwise to offset (-2,1) ..controls (4.41667,13.91667) and (4.375,13.8125) ..(4.3125,13.6875) ..controls (4.125,13.3125) and (3.75,12.75) ..(3,12) % counterclockwise to offset (2,-1) & cycle ] Edge structure at line 158 (just shipped out): Filled pen stroke : (3,12)..controls (3.75,12.75) and (4.125,13.3125) ..(4.3125,13.6875)..controls (4.875,14.8125) and (3.75,14.25) ..(6,12) dashed (on 2 off 1) shifted -1 (this will be ignored) butt ends, mitered joins limited 1 with pen (-2.5,-0.5) .. (-1,-2) .. (0,-2.5) .. (1,-2) .. (2,-1) .. (2.5,0.5) .. (1,2) .. (0,2.5) .. (-1,2) .. (-2,1) .. cycle clipping path: (0,0)..controls (48.28426,-48.28429) and (48.28426,78.28429) ..(0,30)..controls (-8.28427,21.71573) and (-8.28427,8.28427) ..cycle Filled pen stroke colored (0.5,0.5,0.5): (0,0)..controls (10,0) and (20,0) ..(30,0) dashed (on 2 off 1) shifted -1 butt ends, mitered joins limited 1 with pen pencircle transformed (0,0,1.41422,-0.7071,1.41422,0.7071) Filled pen stroke colored (0.5,0.5,0.5): (0,0)..controls (-48.28429,48.28426) and (78.28429,48.28426) ..(30,0) dashed (on 2 off 1) shifted -1 square ends, round joins with pen pencircle transformed (0,0,1.41422,-0.7071,1.41422,0.7071) stop clipping setbounds path: (0,-5.9851)..controls (6.11043,-5.9851) and (12.22087,-5.9851) ..(18.3313,-5.9851)..controls (18.3313,0.65666) and (18.3313,7.29843) ..(18.3313,13.9402)..controls (12.22087,13.9402) and (6.11043,13.9402) ..(0,13.9402)..controls (0,7.29843) and (0,0.65666) ..cycle "Aqua" infont "trapf" colored (0.5,0.5,0.5)transformed (0,-2,1,0,0,1) Filled pen stroke colored (0.5,0.5,0.5): (8.1693,-5.9851)..controls (8.1693,0.65666) and (8.1693,7.29843) ..(8.1693,13.9402) dashed (on 2 off 1) shifted -1 butt ends, round joins with pen pencircle transformed (0,0,1.41422,-0.7071,1.41422,0.7071) "Brass" infont "trapf" colored (0.5,0.5,0.5)transformed (8.3686,-2,2,0,0,2) end of setbounds Filled pen stroke colored (0.5,0.5,0.5): (1,0)..controls (1.33333,0.33333) and (1.66667,0.66667) ..(2,1) dashed (on 2 off 1) shifted -1 square ends, round joins with pen pencircle transformed (0,0,1.41422,-0.7071,1.41422,0.7071) setbounds path: (0,9.0037)..controls (0.66417,9.0037) and (1.32832,9.0037) ..(1.9925,9.0037)..controls (1.9925,11.6604) and (1.9925,14.3171) ..(1.9925,16.9738)..controls (1.32832,16.9738) and (0.66417,16.9738) ..(0,16.9738)..controls (0,14.3171) and (0,11.6604) ..cycle "ast" infont "trapf" transformed (0,10,1,0,0,1) end of setbounds End edges {showstats} Memory usage 3017&264 (273 still untouched) String usage 68&249 (1156&9237 now untouched) {("curb")infont("trapf")} Missing character: There is no c in font trapf! {-(0.5)} {(picture)slanted(-0.5)} {-(1)} {(picture)scaled(-1)} {e6:=picture} {e5:=picture} {showstats} Memory usage 2267&264 (273 still untouched) String usage 66&241 (1155&9233 now untouched) {show} {pencircle} {((0,0))penoffset(pen)} >> (0,0) {llcorner(picture)} >> (-3.98508,-7.97011) {urcorner(picture)} >> (3.98506,1.99254) {(picture)rotated(90)} {(picture)shifted("oops")} >> "oops" ! Improper transformation argument. ; l.161 ...ated 90 shifted "oops"; show llcorner e5, urcorner e5; The expression shown above has the wrong type, so I can't transform anything using it. Proceed, and I'll omit the transformation. {e5:=picture} {show} {llcorner(picture)} >> (-1.99254,-3.98508) {urcorner(picture)} >> (7.97011,3.98506) {show} {char(220)} {("^^dc")infont("trapf")} Missing character: There is no ^^dc in font trapf! {urcorner(picture)} >> (0,0) {makepath(pen)} >> Path at line 162: (-2.5,-0.5)..controls (-2.5,-0.5) and (-1,-2) ..(-1,-2)..controls (-1,-2) and (0,-2.5) ..(0,-2.5)..controls (0,-2.5) and (1,-2) ..(1,-2)..controls (1,-2) and (2,-1) ..(2,-1)..controls (2,-1) and (2.5,0.5) ..(2.5,0.5)..controls (2.5,0.5) and (1,2) ..(1,2)..controls (1,2) and (0,2.5) ..(0,2.5)..controls (0,2.5) and (-1,2) ..(-1,2)..controls (-1,2) and (-2,1) ..(-2,1)..controls (-2,1) and (-2.5,-0.5) ..cycle {show} {-(2)} {-(1)} {((-2,-1))subpath(path)} >> Path at line 163: (0,0) {pencircle} {makepath(pen)} {((9,10))subpath(path)} >> Path at line 163: (0.35355,0.35355)..controls (0.25978,0.44731) and (0.13261,0.5) ..(0,0.5) {("hi")infont("qw99z")} ! Font qw99z not usable: TFM file not found. l.164 "hi" infont "qw99z"; special "ij"="ij"; show substring(... I wasn't able to read the size data for this font so this `infont' operation won't produce anything. If the font name is right, you might ask an expert to make a TFM file Missing character: There is no h in font ! Missing character: There is no i in font ! >> picture ! Isolated expression. ; l.164 "hi" infont "qw99z"; special "ij"="ij"; show substring(... I couldn't find an `=' or `:=' after the expression that is shown above this error message, so I guess I'll just ignore it and carry on. {special} {("ij")=("ij")} >> true ! Unsuitable expression. ; l.164 ...9z"; special "ij"="ij"; show substring(-2,-1)of"abc"; Only known strings are allowed for output as specials. {show} {-(2)} {-(1)} {((-2,-1))substring("abc")} >> "" {addto} {begingroup} {endgroup} >> vacuous ! Improper `addto'. ; l.165 addto e5 contour [[ ]]; addto e5 contour true; pausing:... This expression should have specified a known path. So I'll not change anything just now. {addto} {true} >> true ! Improper `addto'. ; l.165 ... addto e5 contour true; pausing:=0;prologues:=1; This expression should have specified a known path. So I'll not change anything just now. {pausing:=0} {prologues:=1} {charcode:=197} {shipout} [197] Edge structure at line 166 (just shipped out): "curb" infont "trapf" transformed (0,0,0,1,-1,0.5) End edges {-(1)} {-(1)} Path at line 167, before choices: (0,0){2881.87209,2910.67511}..tension atleast1 ..{4096,0}(1,1){-2896.30943,2896.30934} ..{2896.30943,-2896.30934}(2,0) Path at line 167, after choices: (0,0)..controls (0.3493,0.3528) and (0.99011,1) ..(1,1)..controls (0.12732,1.87268) and (1.46066,0.53934) ..(2,0) {(unknown path p~10)=(path)} {prologues:=0} {for} {-(1)} {-(1)} {loop value=(-1,1)} {show} {((-1,1))directiontime(path)} >> 1 {[repeat the loop]} {loop value=(1,-1)} {show} {((1,-1))directiontime(path)} >> 1.2355 {[repeat the loop]} {loop value=(0,0)} {show} {((0,0))directiontime(path)} >> 0 {[repeat the loop]} {linecap:=1} {linejoin:=1} {nullpicture} {e5:=picture} {addto} {pencircle} {(pen)scaled(10)} {makepath(pen)} {pencircle} {(pen)shifted((2,0))} {addto} Path at line 171, before choices: (0,0){curl 1} ..{curl 1}(12,0) Path at line 171, after choices: (0,0)..controls (4,0) and (8,0) ..(12,0) {pencircle} {(pen)yscaled(3)} {charcode:=148} {shipout} [148] Edge structure at line 171 (just shipped out): Filled contour : (5,0)..controls (5,1.32608) and (4.47322,2.59785) ..(3.53554,3.53554)..controls (2.59785,4.47322) and (1.32608,5) ..(0,5)..controls (-1.32608,5) and (-2.59785,4.47322) ..(-3.53554,3.53554)..controls (-4.47322,2.59785) and (-5,1.32608) ..(-5,0)..controls (-5,-1.32608) and (-4.47322,-2.59785) ..(-3.53554,-3.53554)..controls (-2.59785,-4.47322) and (-1.32608,-5) ..(0,-5)..controls (1.32608,-5) and (2.59785,-4.47322) ..(3.53554,-3.53554)..controls (4.47322,-2.59785) and (5,-1.32608) ..cycle round joins with pen pencircle transformed (2,0,1,0,0,1) Filled pen stroke : (0,0)..controls (4,0) and (8,0) ..(12,0) round ends, round joins with pen pencircle transformed (0,0,1,0,0,3) End edges {nullpicture} {e5:=picture} {clip} ! An expression can't begin with `;'. 0 ; l.172 ...llpicture; clip p~8 to; clip e5 to e4; clip e5 to p~... I'm afraid I need some sort of value in order to continue, so I've tentatively inserted `0'. You may want to delete this zero and insert something else; see Chapter 27 of The METAFONTbook for an example. ! Variable p~8 is the wrong type (path). ; l.172 ...llpicture; clip p~8 to; clip e5 to e4; clip e5 to p~... I was looking for a "known" picture variable. So I'll not change anything just now. {clip} >> picture ! Improper `clip'. ; l.172 ... p~8 to; clip e5 to e4; clip e5 to p~8; clip e5 to p~7; This expression should have specified a known path. So I'll not change anything just now. {clip} ! Not a cycle. ; l.172 ... to e4; clip e5 to p~8; clip e5 to p~7; That contour should have ended with `..cycle' or `&cycle'. So I'll not change anything just now. {clip} {addto} {pencircle} {(pen)scaled(50)} {makepath(pen)} {addto} {pencircle} {(pen)xscaled(2)} {addto} {pencircle} {addto} {(path)shifted((10,0))} {(picture)scaled(1)} {pencircle} {charcode:=149} {shipout} [149 Envelope spec at line 177: (25,0) % beginning with offset (2.5,0.5) ..controls (25,6.63042) and (22.36609,12.98926) ..(17.67767,17.67767) % counterclockwise to offset (1,2) ..controls (15.7597,19.59564) and (13.56218,21.16978) ..(11.18088,22.36044) % counterclockwise to offset (0,2.5) ..controls (7.74117,24.08029) and (3.918,25) ..(0,25) ..controls (-3.918,25) and (-7.74117,24.08029) ..(-11.18088,22.36044) % counterclockwise to offset (-1,2) ..controls (-13.56218,21.16978) and (-15.7597,19.59564) ..(-17.67767,17.67767) % counterclockwise to offset (-2,1) ..controls (-20.44812,14.90723) and (-22.50117,11.55353) ..(-23.71729,7.90517) % counterclockwise to offset (-2.5,-0.5) ..controls (-24.5592,5.37941) and (-25,2.71243) ..(-25,0) ..controls (-25,-6.63042) and (-22.36609,-12.98926) ..(-17.67767,-17.67767) % counterclockwise to offset (-1,-2) ..controls (-15.7597,-19.59564) and (-13.56218,-21.16978) ..(-11.18088,-22.36044) % counterclockwise to offset (0,-2.5) ..controls (-7.74117,-24.08029) and (-3.918,-25) ..(0,-25) ..controls (3.918,-25) and (7.74117,-24.08029) ..(11.18088,-22.36044) % counterclockwise to offset (1,-2) ..controls (13.56218,-21.16978) and (15.7597,-19.59564) ..(17.67767,-17.67767) % counterclockwise to offset (2,-1) ..controls (20.44812,-14.90723) and (22.50117,-11.55353) ..(23.71729,-7.90517) % counterclockwise to offset (2.5,0.5) ..controls (24.5592,-5.37941) and (25,-2.71243) ..(25,0) % counterclockwise to offset (-2.5,-0.5) ..controls (25,-2.71243) and (24.5592,-5.37941) ..(23.71729,-7.90517) % clockwise to offset (-2,1) ..controls (22.50117,-11.55353) and (20.44812,-14.90723) ..(17.67767,-17.67767) % clockwise to offset (-1,2) ..controls (15.7597,-19.59564) and (13.56218,-21.16978) ..(11.18088,-22.36044) % clockwise to offset (0,2.5) ..controls (7.74117,-24.08029) and (3.918,-25) ..(0,-25) ..controls (-3.918,-25) and (-7.74117,-24.08029) ..(-11.18088,-22.36044) % clockwise to offset (1,2) ..controls (-13.56218,-21.16978) and (-15.7597,-19.59564) ..(-17.67767,-17.67767) % clockwise to offset (2.5,0.5) ..controls (-22.36609,-12.98926) and (-25,-6.63042) ..(-25,0) ..controls (-25,2.71243) and (-24.5592,5.37941) ..(-23.71729,7.90517) % clockwise to offset (2,-1) ..controls (-22.50117,11.55353) and (-20.44812,14.90723) ..(-17.67767,17.67767) % clockwise to offset (1,-2) ..controls (-15.7597,19.59564) and (-13.56218,21.16978) ..(-11.18088,22.36044) % clockwise to offset (0,-2.5) ..controls (-7.74117,24.08029) and (-3.918,25) ..(0,25) ..controls (3.918,25) and (7.74117,24.08029) ..(11.18088,22.36044) % clockwise to offset (-1,-2) ..controls (13.56218,21.16978) and (15.7597,19.59564) ..(17.67767,17.67767) % clockwise to offset (-2.5,-0.5) ..controls (22.36609,12.98926) and (25,6.63042) ..(25,0) % counterclockwise to offset (2.5,0.5) & cycle ] Edge structure at line 177 (just shipped out): clipping path: (0,0)..controls (48.28426,-48.28429) and (48.28426,78.28429) ..(0,30)..controls (-8.28427,21.71573) and (-8.28427,8.28427) ..cycle stop clipping Filled pen stroke : (25,0)..controls (25,6.63042) and (22.36609,12.98926) ..(17.67767,17.67767)..controls (12.98926,22.36609) and (6.63042,25) ..(0,25)..controls (-6.63042,25) and (-12.98926,22.36609) ..(-17.67767,17.67767)..controls (-22.36609,12.98926) and (-25,6.63042) ..(-25,0)..controls (-25,-6.63042) and (-22.36609,-12.98926) ..(-17.67767,-17.67767)..controls (-12.98926,-22.36609) and (-6.63042,- 25) ..(0,-25)..controls (6.63042,-25) and (12.98926,-22.36609) ..(17.67767,-17.67767)..controls (22.36609,-12.98926) and (25,-6.63042) ..cycle round ends, round joins with pen (-2.5,-0.5) .. (-1,-2) .. (0,-2.5) .. (1,-2) .. (2,-1) .. (2.5,0.5) .. (1,2) .. (0,2.5) .. (-1,2) .. (-2,1) .. cycle Filled pen stroke : (0,0)..controls (-48.28429,48.28426) and (78.28429,48.28426) ..(30,0) dashed (on 2 off 1) shifted -1 round ends, round joins with pen pencircle transformed (0,0,2,0,0,1) Filled pen stroke : (0,0)..controls (-48.28429,48.28426) and (78.28429,48.28426) ..(30,0) dashed (on 2 off 1) shifted -1 round ends, round joins with pen pencircle transformed (0,0,1,0,0,1) Filled pen stroke : (10,0)..controls (-38.28429,48.28426) and (88.28429,48.28426) ..(40,0) dashed (on 2 off 1) shifted -1 round ends, round joins with pen pencircle transformed (0,0,1,0,0,1) End edges {addto} >> 3 ! Not a suitable variable. ; l.177 ...; shipout e5; addto 3; addto p~8 contour p~7; At this point I needed to see the name of a picture variable. (Or perhaps you have indeed presented me with one; I might have missed it, if it wasn't followed by the proper token.) So I'll not change anything just now. {addto} ! Variable p~8 is the wrong type (path). ; l.177 ... addto p~8 contour p~7; I was looking for a "known" picture variable. So I'll not change anything just now. {nullpicture} {e5:=picture} {linecap:=2} {linejoin:=0} {miterlimit:=10} {addto} Path at line 179, before choices: (10,5) ..cycle Path at line 179, after choices: (10,5)..controls (10,5) and (10,5) ..cycle {addto} Path at line 180, before choices: (5,10){curl 1} ..{curl 1}(5,15) Path at line 180, after choices: (5,10)..controls (5,11.66667) and (5,13.33333) ..(5,15) {addto} Path at line 182, before choices: (0,0)..controls (10,10) and (10,10) ..(10,10) ..{curl 1}(0,20){curl 1} ..{curl 1}(30,10) Path at line 182, after choices: (0,0)..controls (10,10) and (10,10) ..(10,10)..controls (6.66667,13.33333) and (3.33333,16.66667) ..(0,20)..controls (10,16.66667) and (20,13.33333) ..(30,10) {-(5)} Path at line 182, before choices: (0,-5) ..(0,5) ..cycle Path at line 182, after choices: (0,-5)..controls (6.66667,-5) and (6.66667,5) ..(0,5)..controls (-6.66667,5) and (-6.66667,-5) ..cycle {makepen(path)} {charcode:=150} {prologues:=1} {shipout} [150 Envelope spec at line 182: (10,5) % beginning with offset (-2.5,-0.5) ..controls (10,5) and (10,5) ..(10,5) % counterclockwise to offset (-2.5,-0.5) & cycle Envelope spec at line 182: (10,5) % beginning with offset (-2.5,-0.5) ..controls (10,5) and (10,5) ..(10,5) % counterclockwise to offset (-2.5,-0.5) & cycle Envelope spec at line 182: (5,10) % beginning with offset (2.5,0.5) ..controls (5,11.66667) and (5,13.33333) ..(5,15) % counterclockwise to offset (-2.5,-0.5) ..controls (5,13.33333) and (5,11.66667) ..(5,10) % counterclockwise to offset (2.5,0.5) & cycle Envelope spec at line 182: (0,0) % beginning with offset (0,-5) ..controls (10,10) and (10,10) ..(10,10) % counterclockwise to offset (0,5) ..controls (6.66667,13.33333) and (3.33333,16.66667) ..(0,20) % clockwise to offset (0,-5) ..controls (10,16.66667) and (20,13.33333) ..(30,10) % counterclockwise to offset (0,5) ..controls (20,13.33333) and (10,16.66667) ..(0,20) % counterclockwise to offset (0,-5) ..controls (3.33333,16.66667) and (6.66667,13.33333) ..(10,10) % clockwise to offset (0,5) ..controls (10,10) and (10,10) ..(0,0) % counterclockwise to offset (0,-5) & cycle ] Edge structure at line 182 (just shipped out): Filled contour : (10,5)..controls (10,5) and (10,5) ..cycle mitered joins limited 10 with pen (-2.5,-0.5) .. (-1,-2) .. (0,-2.5) .. (1,-2) .. (2,-1) .. (2.5,0.5) .. (1,2) .. (0,2.5) .. (-1,2) .. (-2,1) .. cycle Filled pen stroke : (5,10)..controls (5,11.66667) and (5,13.33333) ..(5,15) square ends, mitered joins limited 10 with pen (-2.5,-0.5) .. (-1,-2) .. (0,-2.5) .. (1,-2) .. (2,-1) .. (2.5,0.5) .. (1,2) .. (0,2.5) .. (-1,2) .. (-2,1) .. cycle Filled pen stroke : (0,0)..controls (10,10) and (10,10) ..(10,10)..controls (6.66667,13.33333) and (3.33333,16.66667) ..(0,20)..controls (10,16.66667) and (20,13.33333) ..(30,10) square ends, mitered joins limited 10 with pen (0,-5) .. (0,5) .. cycle End edges {for} {sqrt(-1)} ! Square root of -1 has been replaced by 0. l.183 for @=angle(sqrt$, mlog$):charext:=uniformdeviate$;charh... Since I don't take square roots of negative numbers, I'm zeroing this one. Proceed, with fingers crossed. {mlog(-1)} ! Logarithm of -1 has been replaced by 0. l.183 for @=angle(sqrt$,mlog$) :charext:=uniformdeviate$;charh... Since I don't take logs of non-positive numbers, I'm zeroing this one. Proceed, with fingers crossed. {angle((0,0))} ! angle(0,0) is taken as zero. l.183 for @=angle(sqrt$,mlog$): charext:=uniformdeviate$;charh... The `angle' between two identical points is undefined. I'm zeroing this one. Proceed, with fingers crossed. Runaway loop? charext:=uniformdeviate$;charht:=2048;addto.e3contour( ETC. ! Forbidden token found while scanning the text of a for loop. endfor endtext l.206 ... showstats; bye endtext I suspect you have forgotten an `endfor', causing me to read past where you wanted me to stop. I'll try to recover; but if the error is serious, you'd better type `E' or `X' now and fix your file. {loop value=0} {uniformdeviate(-1)} {charext:=-0.00507} {charht:=2048} {addto} {-(100)} {-(99)} Path at line 206, before choices: (0,-100)..tension 500 ..(100,-99)..tension 3000 ..cycle Path at line 206, after choices: (0,-100)..controls (-36.92659,-103.51175) and (136.98943,-101.7726) ..(100,-99)..controls (99.9889,-98.99916) and (0.01108,-99.99895) ..cycle {tracingoutput:=0} {special} {charcode:=151} {shipout} ! Enormous charht has been reduced. ; ...ode:=151;shipout.e3; interim.char99="c";true=false... endfor endtext l.206 ... showstats; bye endtext Font metric dimensions must be less than 2048pt. [151 Envelope spec at line 206: (0,0) % beginning with offset (-1,-2) ..controls (0.04324,-0.04068) and (0.08835,-0.07198) ..(0.13504,-0.09532) % counterclockwise to offset (0,-2.5) ..controls (0.64822,-0.3519) and (1.35178,0.35191) ..(1.86496,0.09532) % clockwise to offset (-1,-2) ..controls (1.91165,0.07198) and (1.95676,0.04068) ..(2,0) ..controls (2.00706,-0.00664) and (2.01395,-0.01332) ..(2.02066,-0.02003) % clockwise to offset (-2.5,-0.5) ..controls (2.2398,-0.23918) and (2.27596,-0.49583) ..(2.2023,-0.71681) % clockwise to offset (-2,1) ..controls (2.16501,-0.82869) and (2.09958,-0.93141) ..(2.01549,-1.0155) % clockwise to offset (-1,2) ..controls (1.95589,-1.0751) and (1.88692,-1.12534) ..(1.81195,-1.16281) % clockwise to offset (0,2.5) ..controls (1.63397,-1.2518) and (1.42226,-1.26889) ..(1.22209,-1.16881) % clockwise to offset (1,2) ..controls (1.15273,-1.13412) and (1.08475,-1.08539) ..(1.02003,-1.02068) % clockwise to offset (2.5,0.5) ..controls (1.01332,-1.01396) and (1.00664,-1.00706) ..(1,-1) ..controls (0.78389,-0.77028) and (0.83284,-0.488) ..(0.93013,-0.19617) % clockwise to offset (2,-1) ..controls (0.97351,-0.06602) and (1.0265,0.06602) ..(1.06989,0.19617) % counterclockwise to offset (2.5,0.5) ..controls (1.16716,0.488) and (1.21611,0.77028) ..(1,1) ..controls (0.99336,1.00706) and (0.98668,1.01395) ..(0.97997,1.02066) % counterclockwise to offset (1,2) ..controls (0.91525,1.08537) and (0.84727,1.13412) ..(0.77791,1.16881) % counterclockwise to offset (0,2.5) ..controls (0.57773,1.26889) and (0.36601,1.2518) ..(0.18803,1.16281) % counterclockwise to offset (-1,2) ..controls (0.11307,1.12534) and (0.0441,1.0751) ..(-0.0155,1.0155) % counterclockwise to offset (-2,1) ..controls (-0.09958,0.93141) and (-0.16502,0.82869) ..(-0.20232,0.71681) % counterclockwise to offset (-2.5,-0.5) ..controls (-0.27597,0.49583) and (-0.2398,0.2392) ..(-0.02066,0.02003) % counterclockwise to offset (-1,-2) ..controls (-0.01395,0.01332) and (-0.00706,0.00664) ..(0,0) & cycle Envelope spec at line 206: (0,0) % beginning with offset (1,2) ..controls (-0.00706,0.00664) and (-0.01395,0.01332) ..(-0.02066,0.02003) % clockwise to offset (2.5,0.5) ..controls (-0.2398,0.23918) and (-0.27596,0.49583) ..(-0.2023,0.71681) % clockwise to offset (2,-1) ..controls (-0.16501,0.82869) and (-0.09958,0.93141) ..(-0.01549,1.0155) % clockwise to offset (1,-2) ..controls (0.04411,1.0751) and (0.11308,1.12534) ..(0.18805,1.16281) % clockwise to offset (0,-2.5) ..controls (0.36603,1.2518) and (0.57774,1.26889) ..(0.77791,1.16881) % clockwise to offset (-1,-2) ..controls (0.84727,1.13412) and (0.91525,1.08539) ..(0.97997,1.02068) % clockwise to offset (-2.5,-0.5) ..controls (0.98668,1.01396) and (0.99336,1.00706) ..(1,1) ..controls (1.21611,0.77028) and (1.16716,0.488) ..(1.06987,0.19617) % clockwise to offset (-2,1) ..controls (1.02649,0.06602) and (0.9735,-0.06602) ..(0.93011,-0.19617) % counterclockwise to offset (-2.5,-0.5) ..controls (0.83284,-0.488) and (0.78389,-0.77028) ..(1,-1) ..controls (1.00664,-1.00706) and (1.01332,-1.01395) ..(1.02003,-1.02066) % counterclockwise to offset (-1,-2) ..controls (1.08475,-1.08537) and (1.15273,-1.13412) ..(1.22209,-1.16881) % counterclockwise to offset (0,-2.5) ..controls (1.42227,-1.26889) and (1.63399,-1.2518) ..(1.81197,-1.16281) % counterclockwise to offset (1,-2) ..controls (1.88693,-1.12534) and (1.9559,-1.0751) ..(2.0155,-1.0155) % counterclockwise to offset (2,-1) ..controls (2.09958,-0.93141) and (2.16502,-0.82869) ..(2.20232,-0.71681) % counterclockwise to offset (2.5,0.5) ..controls (2.27597,-0.49583) and (2.2398,-0.2392) ..(2.02066,-0.02003) % counterclockwise to offset (1,2) ..controls (2.01395,-0.01332) and (2.00706,-0.00664) ..(2,0) ..controls (1.95676,0.04068) and (1.91165,0.07198) ..(1.86496,0.09532) % counterclockwise to offset (0,2.5) ..controls (1.35178,0.3519) and (0.64822,-0.35191) ..(0.13504,-0.09532) % clockwise to offset (1,2) ..controls (0.08835,-0.07198) and (0.04324,-0.04068) ..(0,0) & cycle Envelope spec at line 206: (0,0) % beginning with offset (1,-2) ..controls (0.17854,0.17854) and (0.38548,0.31178) ..(0.60698,0.42253) % clockwise to offset (0,-2.5) ..controls (1.04999,0.64404) and (1.55122,0.77562) ..(1.99995,1) % counterclockwise to offset (1,-2) ..controls (1.99997,1) and (1.99998,1) ..(2,1) % counterclockwise to offset (-1,2) ..controls (1.99998,1) and (1.99997,1) ..(1.99995,1) % clockwise to offset (0,2.5) ..controls (1.55122,0.77562) and (1.05,0.64404) ..(0.607,0.42253) % counterclockwise to offset (-1,2) ..controls (0.3855,0.31178) and (0.17856,0.17856) ..(0,0) % counterclockwise to offset (1,-2) & cycle Envelope spec at line 206: (0,257) % beginning with offset (-1,-2) ..controls (0.04324,256.95932) and (0.08835,256.92802) ..(0.13504,256.90468) % counterclockwise to offset (0,-2.5) ..controls (0.64822,256.6481) and (1.35178,257.35191) ..(1.86496,257.09532) % clockwise to offset (-1,-2) ..controls (1.91165,257.07198) and (1.95676,257.04068) ..(2,257) ..controls (2.00706,256.99336) and (2.01395,256.98668) ..(2.02066,256.97997) % clockwise to offset (-2.5,-0.5) ..controls (2.2398,256.76082) and (2.27596,256.50417) ..(2.2023,256.28319) % clockwise to offset (-2,1) ..controls (2.16501,256.17131) and (2.09958,256.06859) ..(2.01549,255.9845) % clockwise to offset (-1,2) ..controls (1.95589,255.9249) and (1.88692,255.87466) ..(1.81195,255.83719) % clockwise to offset (0,2.5) ..controls (1.63397,255.7482) and (1.42226,255.73111) ..(1.22209,255.83119) % clockwise to offset (1,2) ..controls (1.15273,255.86588) and (1.08475,255.91461) ..(1.02003,255.97932) % clockwise to offset (2.5,0.5) ..controls (1.01332,255.98604) and (1.00664,255.99294) ..(1,256) ..controls (0.78389,256.22972) and (0.83284,256.512) ..(0.93013,256.80383) % clockwise to offset (2,-1) ..controls (0.97351,256.93398) and (1.0265,257.06602) ..(1.06989,257.19617) % counterclockwise to offset (2.5,0.5) ..controls (1.16716,257.488) and (1.21611,257.77028) ..(1,258) ..controls (0.99336,258.00706) and (0.98668,258.01395) ..(0.97997,258.02066) % counterclockwise to offset (1,2) ..controls (0.91525,258.08537) and (0.84727,258.13412) ..(0.77791,258.16881) % counterclockwise to offset (0,2.5) ..controls (0.57773,258.26889) and (0.36601,258.2518) ..(0.18803,258.16281) % counterclockwise to offset (-1,2) ..controls (0.11307,258.12534) and (0.0441,258.0751) ..(-0.0155,258.0155) % counterclockwise to offset (-2,1) ..controls (-0.09958,257.93141) and (-0.16502,257.82869) ..(-0.20232,257.71681) % counterclockwise to offset (-2.5,-0.5) ..controls (-0.27597,257.49583) and (-0.2398,257.2392) ..(-0.02066,257.02003) % counterclockwise to offset (-1,-2) ..controls (-0.01395,257.01332) and (-0.00706,257.00664) ..(0,257) & cycle Envelope spec at line 206: (0,257) % beginning with offset (1,2) ..controls (-0.00706,257.00664) and (-0.01395,257.01332) ..(-0.02066,257.02003) % clockwise to offset (2.5,0.5) ..controls (-0.2398,257.23918) and (-0.27596,257.49583) ..(-0.2023,257.71681) % clockwise to offset (2,-1) ..controls (-0.16501,257.82869) and (-0.09958,257.93141) ..(-0.01549,258.0155) % clockwise to offset (1,-2) ..controls (0.04411,258.0751) and (0.11308,258.12534) ..(0.18805,258.16281) % clockwise to offset (0,-2.5) ..controls (0.36603,258.2518) and (0.57774,258.26889) ..(0.77791,258.16881) % clockwise to offset (-1,-2) ..controls (0.84727,258.13412) and (0.91525,258.08539) ..(0.97997,258.02068) % clockwise to offset (-2.5,-0.5) ..controls (0.98668,258.01396) and (0.99336,258.00706) ..(1,258) ..controls (1.21611,257.77028) and (1.16716,257.488) ..(1.06987,257.19617) % clockwise to offset (-2,1) ..controls (1.02649,257.06602) and (0.9735,256.93398) ..(0.93011,256.80383) % counterclockwise to offset (-2.5,-0.5) ..controls (0.83284,256.512) and (0.78389,256.22972) ..(1,256) ..controls (1.00664,255.99294) and (1.01332,255.98605) ..(1.02003,255.97934) % counterclockwise to offset (-1,-2) ..controls (1.08475,255.91463) and (1.15273,255.86588) ..(1.22209,255.83119) % counterclockwise to offset (0,-2.5) ..controls (1.42227,255.73111) and (1.63399,255.7482) ..(1.81197,255.83719) % counterclockwise to offset (1,-2) ..controls (1.88693,255.87466) and (1.9559,255.9249) ..(2.0155,255.9845) % counterclockwise to offset (2,-1) ..controls (2.09958,256.06859) and (2.16502,256.17131) ..(2.20232,256.28319) % counterclockwise to offset (2.5,0.5) ..controls (2.27597,256.50417) and (2.2398,256.7608) ..(2.02066,256.97997) % counterclockwise to offset (1,2) ..controls (2.01395,256.98668) and (2.00706,256.99336) ..(2,257) ..controls (1.95676,257.04068) and (1.91165,257.07198) ..(1.86496,257.09532) % counterclockwise to offset (0,2.5) ..controls (1.35178,257.3519) and (0.64822,256.64809) ..(0.13504,256.90468) % clockwise to offset (1,2) ..controls (0.08835,256.92802) and (0.04324,256.95932) ..(0,257) & cycle Envelope spec at line 206: (0,257) % beginning with offset (1,-2) ..controls (0.17854,257.17854) and (0.38548,257.31178) ..(0.60698,257.42253) % clockwise to offset (0,-2.5) ..controls (1.04999,257.64404) and (1.55122,257.77562) ..(1.99995,258) % counterclockwise to offset (1,-2) ..controls (1.99997,258) and (1.99998,258) ..(2,258) % counterclockwise to offset (-1,2) ..controls (1.99998,258) and (1.99997,258) ..(1.99995,258) % clockwise to offset (0,2.5) ..controls (1.55122,257.77562) and (1.05,257.64404) ..(0.607,257.42253) % counterclockwise to offset (-1,2) ..controls (0.3855,257.31178) and (0.17856,257.17856) ..(0,257) % counterclockwise to offset (1,-2) & cycle ] {interim} ! The token `char' isn't an internal quantity. char ...pout.e3;interim.char 99="c";true=false;show.penoff... endfor endtext l.206 ... showstats; bye endtext Something like `tracingonline' should follow `interim'. {char(99)} {("c")=("c")} ! Redundant equation. ; ...;interim.char99="c"; true=false;show.penoffset(2,1... endfor endtext l.206 ... showstats; bye endtext I already knew that this equation was true. But perhaps no harm has been done; let's continue. {true} {false} {(true)=(false)} ! Inconsistent equation. ; ...ar99="c";true=false; show.penoffset(2,1)of.qq;show... endfor endtext l.206 ... showstats; bye endtext The equation I just read contradicts what was said before. But don't worry; continue and I'll just ignore it. {show} {((2,1))penoffset(pen)} >> (0,-2.5) {showstats} Memory usage 2744&607 (39 still untouched) String usage 73&279 (1139&9160 now untouched) {let} {showtoken} > f=tag {showstats} Memory usage 2704&536 (39 still untouched) String usage 73&279 (1139&9160 now untouched) {nullpicture} {(unknown picture e17)=(picture)} {addto} {-(4)} {-(5)} Path at line 206, before choices: (-4,-5){curl 1} ..{curl 1}(6,5) Path at line 206, after choices: (-4,-5)..controls (-0.66667,-1.66667) and (2.66667,1.66667) ..(6,5) {setbounds} {pencircle} {(pen)scaled(9)} {makepath(pen)} {show} {llcorner(picture)} >> (-4.5,-4.5) {urcorner(picture)} >> (4.5,4.5) {addto} {-(5)} {-(5)} {(picture)shifted((-5,-5))} {show} {llcorner(picture)} >> (-9.5,-9.5) {truecorners:=2} {show} {llcorner(picture)} >> (-9,-10) {-(1)} {truecorners:=-1} {setbounds} {pencircle} {(pen)xscaled(19)} {makepath(pen)} {addto} {-(5)} {-(10)} {(picture)shifted((-5,-10))} {show} {llcorner(picture)} >> (-14.5,-10.5) >> Edge structure at line 206: Filled contour : (10,5)..controls (10,5) and (10,5) ..cycle mitered joins limited 10 with pen (-2.5,-0.5) .. (-1,-2) .. (0,-2.5) .. (1,-2) .. (2,-1) .. (2.5,0.5) .. (1,2) .. (0,2.5) .. (-1,2) .. (-2,1) .. cycle Filled pen stroke : (5,10)..controls (5,11.66667) and (5,13.33333) ..(5,15) square ends, mitered joins limited 10 with pen (-2.5,-0.5) .. (-1,-2) .. (0,-2.5) .. (1,-2) .. (2,-1) .. (2.5,0.5) .. (1,2) .. (0,2.5) .. (-1,2) .. (-2,1) .. cycle Filled pen stroke : (0,0)..controls (10,10) and (10,10) ..(10,10)..controls (6.66667,13.33333) and (3.33333,16.66667) ..(0,20)..controls (10,16.66667) and (20,13.33333) ..(30,10) square ends, mitered joins limited 10 with pen (0,-5) .. (0,5) .. cycle setbounds path: (-0.5,-5)..controls (-0.5,-3.80652) and (-0.9741,-2.66194) ..(-1.81802,-1.81802)..controls (-2.66194,-0.9741) and (-3.80652,-0.5) ..(-5,-0.5)..controls (-6.19348,-0.5) and (-7.33806,-0.9741) ..(-8.18198,-1.81802)..controls (-9.0259,-2.66194) and (-9.5,-3.80652) ..(-9.5,-5)..controls (-9.5,-6.19348) and (-9.0259,-7.33806) ..(-8.18198,-8.18198)..controls (-7.33806,-9.0259) and (-6.19348,-9.5) ..(-5,-9.5)..controls (-3.80652,-9.5) and (-2.66194,-9.0259) ..(-1.81802,-8.18198)..controls (-0.9741,-7.33806) and (-0.5,-6.19348) ..cycle Filled pen stroke : (-9,-10)..controls (-5.66667,-6.66667) and (-2.33333,-3.33333) ..(1,0) square ends, mitered joins limited 10 with pen pencircle transformed (0,0,0,0,0,0) end of setbounds setbounds path: (4.5,-10)..controls (4.5,-9.86739) and (3.49911,-9.74022) ..(1.71751,-9.64645)..controls (-0.06409,-9.55269) and (-2.48044,-9.5) ..(-5,-9.5)..controls (-7.51956,-9.5) and (-9.93591,-9.55269) ..(-11.71751,-9.64645)..controls (-13.49911,-9.74022) and (-14.5,-9.867 39) ..(-14.5,-10)..controls (-14.5,-10.13261) and (-13.49911,-10.25978) ..(-11.71751,-10.35355)..controls (-9.93591,-10.44731) and (-7.51956,-1 0.5) ..(-5,-10.5)..controls (-2.48044,-10.5) and (-0.06409,-10.44731) ..(1.71751,-10.35355)..controls (3.49911,-10.25978) and (4.5,-10.13261) ..cycle setbounds path: (-0.5,-10)..controls (-0.5,-8.80652) and (-0.9741,-7.66194) ..(-1.81802,-6.81802)..controls (-2.66194,-5.9741) and (-3.80652,-5.5) ..(-5,-5.5)..controls (-6.19348,-5.5) and (-7.33806,-5.9741) ..(-8.18198,-6.81802)..controls (-9.0259,-7.66194) and (-9.5,-8.80652) ..(-9.5,-10)..controls (-9.5,-11.19348) and (-9.0259,-12.33806) ..(-8.18198,-13.18198)..controls (-7.33806,-14.0259) and (-6.19348,-14. 5) ..(-5,-14.5)..controls (-3.80652,-14.5) and (-2.66194,-14.0259) ..(-1.81802,-13.18198)..controls (-0.9741,-12.33806) and (-0.5,-11.1934 8) ..cycle Filled pen stroke : (-9,-15)..controls (-5.66667,-11.66667) and (-2.33333,-8.33333) ..(1,-5) square ends, mitered joins limited 10 with pen pencircle transformed (0,0,0,0,0,0) end of setbounds end of setbounds End edges {pencircle} {urcorner(pen)} >> (0.5,0.5) {nullpicture} {e5:=picture} {path} {pencircle} {(pen)scaled(100)} {makepath(pen)} {(unknown path ap1)=(path)} {-(14)} {-(7)} Path at line 206, before choices: (2,-14)..controls (14,-7) and (14,7) ..(2,14) Path at line 206, after choices: (2,-14)..controls (14,-7) and (14,7) ..(2,14) {(unknown path ap2)=(path)} {-(50)} {-(50)} Path at line 206, before choices: (-50,0)..controls (-50,0) and (-50,0) ..(50,0) Path at line 206, after choices: (-50,0)..controls (-50,0) and (-50,0) ..(50,0) {(unknown path ap3)=(path)} {show} {(path)scaled(1000)} {arclength(path)} ! Arithmetic overflow. ...ngth(ap2scaled1000), arclength(ap3scaled200);show.... endfor endtext l.206 ... showstats; bye endtext Uh, oh. A little while ago one of the quantities that I was computing got too large, so I'm afraid your answers will be somewhat askew. You'll probably have to adopt different tactics next time. But I shall try to carry on anyway. >> 32767.99998 {(path)scaled(200)} {arclength(path)} ! Arithmetic overflow. ...ength(ap3scaled200); show.arclength.ap1,arclength.... endfor endtext l.206 ... showstats; bye endtext Uh, oh. A little while ago one of the quantities that I was computing got too large, so I'm afraid your answers will be somewhat askew. You'll probably have to adopt different tactics next time. But I shall try to carry on anyway. >> 32767.99998 {show} {arclength(path)} >> 314.15979 {arclength(path)} >> 34.88 {show} {(6.4)arctime(path)} >> 0.4 {(37)arctime(path)} {((0,0.7179))subpath(path)} {arclength(path)} >> 36.99847 {show} {-(1000)} {(-1000)arctime(path)} >> -25.46454 {-(3)} {(-3)arctime(path)} >> 0 {(path)scaled(0.00002)} {(314)arctime(path)} ! Arithmetic overflow. ...f(ap1scaled0.00002); [[clear(tracingcommands);char... endfor endtext l.206 ... showstats; bye endtext Uh, oh. A little while ago one of the quantities that I was computing got too large, so I'm afraid your answers will be somewhat askew. You'll probably have to adopt different tactics next time. But I shall try to carry on anyway. >> 32767.99998 {begingroup} clear(TEXT0)->interim(TEXT0):=$ (TEXT0)<-tracingcommands {interim} {tracingcommands:=-1} ! Enormous charht has been reduced. ; ...shipout.nullpicture; "careful"for.for=(EXPR0)step2... endfor endtext l.206 ... showstats; bye endtext Font metric dimensions must be less than 2048pt. [0] careful METAFONT METAFONT METAFONT METAFONT METAFONT METAFONT METAFONT M ETAFONT METAFONT METAFONT METAFONT METAFONT METAFONT METAFONT METAFONT M ETAFONT METAFONT METAFONT METAFONT METAFONT METAFONT METAFONT METAFONT M ETAFONT METAFONT METAFONT METAFONT {restoring tracingcommands=2.1} {endgroup} {scrollmode} {char(31)} {("hello again")&("^^_")} hello again^^_ {save} ### -0.45p3~=-alpha+7 {def} {begingroup} {tracingonline:=1} {tracingonline:=1} f->let)=];let[=(;show._ (EXPR0)<-xx {let} {let} {show} >> _1 {showdependencies} xpart '=-ypart '-0.66667 {qq:=pen} {showstats} Memory usage 2147&536 (39 still untouched) String usage 73&277 (1112&5817 now untouched) {[repeat the loop]} >> bye ! Isolated expression. endtext l.206 ... showstats; bye endtext I couldn't find an `=' or `:=' after the expression that is shown above this error message, so I guess I'll just ignore it and carry on. ! Extra tokens will be flushed. endtext l.206 ... showstats; bye endtext I've just read as much of that statement as I could fathom, so a semicolon should have been next. It's very puzzling... but I'll try to get myself back together, by ignoring everything up to the next `;'. Please insert a semicolon now in front of anything that you don't want me to delete. (See Chapter 27 of The METAFONTbook for an example.) ! Forbidden token found while scanning to the end of the statement. ; endtext l.206 ... showstats; bye endtext A previous error seems to have propagated, causing me to read past where you wanted me to stop. I'll try to recover; but if the error is serious, you'd better type `E' or `X' now and fix your file. {show} ) *end ! An expression can't begin with `end'. 0 end <*> end I'm afraid I need some sort of value in order to continue, so I've tentatively inserted `0'. You may want to delete this zero and insert something else; see Chapter 27 of The METAFONTbook for an example. >> 0 ! A group begun on line 206 never ended. end <*> end I saw a `begingroup' back there that hasn't been matched by `endgroup'. So I've inserted `endgroup' now. {endgroup} (end occurred when else on line 88 was incomplete) (end occurred when if on line 37 was incomplete) (end occurred when elseif on line 22 was incomplete) Here is how much of MetaPost's memory you used: 75 strings out of 1276 768 string characters out of 9771 4462 words of memory out of 4501 338 symbolic tokens out of 2100 8i,35n,8p,167b stack positions out of 30i,100n,150p,500b 0 string compactions (moved 0 characters, 0 strings) (illegal design size has been changed to 128pt) (some chardp values had to be adjusted by as much as 0.5pt) (local label 0:: was missing) (local label 5:: was missing) (4 font metric dimensions had to be decreased) (You used 3w,2h,16d,2i,312l,301k,1e,10p metric file positions out of 256w,16h,16d,64i,5000l,500k,256e,50p) Font metrics written on trap.tfm. 25 output files written: trap.ps .. trap.200