#include #include #include "map.h" /* Given two lat-lon pairs, find an orientation for the -o option of "map" that will place those two points on the equator of a standard projection, equally spaced about the prime meridian. -w and -l options are suggested also. Option -t prints out a series of coordinates that follows the (great circle) track in the original coordinate system, followed by ". This data is just right for map -t. Option -i inverts the map top-to-bottom. */ struct place pole; struct coord twist; int track; int inv = -1; extern void doroute(double, double, double, double, double); void dorot(double a, double b, double *x, double *y, void (*f)(struct place *)) { struct place g; deg2rad(a,&g.nlat); deg2rad(b,&g.wlon); (*f)(&g); *x = g.nlat.l/RAD; *y = g.wlon.l/RAD; } void rotate(double a, double b, double *x, double *y) { dorot(a,b,x,y,normalize); } void rinvert(double a, double b, double *x, double *y) { dorot(a,b,x,y,invert); } main(int argc, char **argv) { #pragma ref argv double an,aw,bn,bw; ARGBEGIN { case 't': track = 1; break; case 'i': inv = 1; break; default: exits("route: bad option"); } ARGEND; if (argc<4) { print("use route [-t] [-i] lat lon lat lon\n"); exits("arg count"); } an = atof(argv[0]); aw = atof(argv[1]); bn = atof(argv[2]); bw = atof(argv[3]); doroute(inv*90.,an,aw,bn,bw); return 0; } void doroute(double dir, double an, double aw, double bn, double bw) { double an1,aw1,bn1,bw1,pn,pw; double theta; double cn,cw,cn1,cw1; int i,n; orient(an,aw,0.); rotate(bn,bw,&bn1,&bw1); /* printf("b %f %f\n",bn1,bw1);*/ orient(an,aw,bw1); rinvert(0.,dir,&pn,&pw); /* printf("p %f %f\n",pn,pw);*/ orient(pn,pw,0.); rotate(an,aw,&an1,&aw1); rotate(bn,bw,&bn1,&bw1); theta = (aw1+bw1)/2; /* printf("a %f %f \n",an1,aw1);*/ orient(pn,pw,theta); rotate(an,aw,&an1,&aw1); rotate(bn,bw,&bn1,&bw1); if(fabs(aw1-bw1)>180) if(theta<0.) theta+=180; else theta -= 180; orient(pn,pw,theta); rotate(an,aw,&an1,&aw1); rotate(bn,bw,&bn1,&bw1); if(!track) { double dlat, dlon, t; /* printf("A %.4f %.4f\n",an1,aw1); */ /* printf("B %.4f %.4f\n",bn1,bw1); */ cw1 = fabs(bw1-aw1); /* angular difference for map margins */ /* while (aw<0.0) aw += 360.; while (bw<0.0) bw += 360.; */ dlon = fabs(aw-bw); if (dlon>180) dlon = 360-dlon; dlat = fabs(an-bn); printf("-o %.4f %.4f %.4f -w %.2f %.2f %.2f %.2f \n", pn,pw,theta, -0.3*cw1, .3*cw1, -.6*cw1, .6*cw1); } else { cn1 = 0; n = 1 + fabs(bw1-aw1)/.2; for(i=0;i<=n;i++) { cw1 = aw1 + i*(bw1-aw1)/n; rinvert(cn1,cw1,&cn,&cw); printf("%f %f\n",cn,cw); } printf("\"\n"); } }